Understanding X-Ray Spectra Graphs

AI Thread Summary
The discussion centers on understanding x-ray spectra graphs, specifically the relationship between intensity and wavelength. It clarifies that the intensity at any wavelength is influenced by both the energy of individual photons and their quantity. The minimum wavelength corresponds to a scenario where the intensity is nearly zero, as it occurs during rare collisions where all kinetic energy is converted into a photon. The graph represents a distribution of x-ray energies rather than specific energies produced at certain intensities. Overall, the confusion arises from misinterpreting the intensity as related to the bombarding electrons rather than the emitted x-ray photons.
Snowy
Messages
4
Reaction score
0
just been learning how to produce x-rays by firing electrons at heavy atoms, but i am a tad confused about the x-ray spectra graph with 'intensity' on the y and 'wavelength' on the x. it shows that the minimum wavelenth is produced wen intensity=0. how is this possible?
 
Physics news on Phys.org
Snowy said:
just been learning how to produce x-rays by firing electrons at heavy atoms, but i am a tad confused about the x-ray spectra graph with 'intensity' on the y and 'wavelength' on the x. it shows that the minimum wavelenth is produced wen intensity=0. how is this possible?

The details of the spectrum are complicated, so this is not a full explanation why the intensity spectrum looks the way it does. It will help you though to understand that the intensity at any wavelength depends on both the energy of the individual photons, and the number of photons produced at that energy. A detailed examination of the collisions of electrons with heavy nucleii will show that the kind of collision that results in the shortest wavelength photons is far less likely than collisions that produce longer wavelengths. The longer wavelength photons are produced in greater numbers, but the intensity gradually decreases because of the lower energy per photon. There is no limit on how long the wavelength can be, which is why there are those long tails on the right side of the spectrum curve. There is a limit on how short the wavelength can be, depending on the initial velocity (or kinetic energy) of the electron. That is why the curves show a lower left end of the spectrum as the electron energy increases.

http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/xrayc.html#c2
 
Snowy said:
just been learning how to produce x-rays by firing electrons at heavy atoms, but i am a tad confused about the x-ray spectra graph with 'intensity' on the y and 'wavelength' on the x. it shows that the minimum wavelenth is produced wen intensity=0. how is this possible?

the x-ray spectrum is just a histogram showing the distribution of the various x-ray energies in the beam, not what x-ray energies/wavelengths are produced at particular intensities. All the spectrum tells you is that for that particular beam, at a wavelength of x nm or x eV, you will see an intensity of y. At the minimum wavelength (maximum x-ray energy), the intensity of the beam is 0 (none or very little).
 
Just to underscore what has already been said, the minimum wavelength (highest energy) photon is created in the rare event when ALL the kinetic energy of an elecron is converted into a photon. At this point the intensity is "almost zero." Since two electrons can't "gang up" their energies, no photons of higher energy than this can be created.

According to my read of your question, this may be your concern:
The point on the graph you are looking at for "minimum wavelength" is actually an infinitessimally small increment to the right of the "zero" intensity point. For all practical purposes, you just read the "zero" point.
 
ok thanks everyone. Think i somehow confused myself into thinking that intensity reffered 2 the bombarding electrons.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top