Various RLC Circuit Problems (Resonance Frequency, Phase, Current)

AI Thread Summary
The discussion focuses on solving various problems related to an RLC circuit with given values for inductance, resistance, and capacitance. The resonance frequency was recalculated and found to be approximately 447.21 Hz. For a frequency of 400 rad/s, the phase angle was determined to be -0.0057°, and the circuit impedance was calculated to be around 20000.0001 Ω. The current function over time was derived as I(t) = 0.0015sin(400t). Participants expressed confusion regarding the phasor diagram but sought guidance on how to approach it.
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Homework Statement


An RLC circuit has L = 20mH, R = 20kΩ, C = 250μF.

1) Calculate the resonance frequency for this circuit.

2) For a frequency ω=400 rad/s, determine the phase angle and the circuit impedance.

3) Using ε = 30[V]sin(ωt), calculate the current in the circuit. This will be a function of time.

4) Draw the phasor diagram for t=0 seconds.

Homework Equations


ω_{o} = \frac{1}{\sqrt{LC}}

ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right]

X_{L} = ωL

X_{C} = \frac{1}{ωC}

Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}

I(t) = \frac{ε}{Z}

The Attempt at a Solution


So I wasn't sure if I was doing any of this correctly; with all of the formulas/equations, it looked like the questions were mostly some simple plug-in questions, but I feel like my numbers just weren't coming out quite right.

1) Calculate the resonance frequency for this circuit.

ω_{o} = \frac{1}{\sqrt{LC}}
L = 20mH = 0.02H; C = 250μF
ω_{o} = \frac{1}{\sqrt{(0.02H)(250μF)}} = \frac{1}{2.24 sec} = 0.447 Hz

2) For a frequency ω=400 rad/s, determine the phase angle and the circuit impedance.
Phase Angle ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right]

X_{L} = ωL = (400)(0.02) = 8
X_{C} = \frac{1}{(400)(250)} = \frac{1}{100,000} = 0.00001
R = 20kΩ

ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right] = tan^{-1} \left[\frac{8-0.00001}{20,000}\right] = tan^{-1} \left[\frac{7.99999}{20,000}\right] = tan^{-1} \left[3.99x10^{-4}\right] = 0.0229°

Impedance Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}} = \sqrt{20,000^{2} + (8 - 0.00001)^{2}} = \sqrt{4.0x10^{8} + 63.99} = 20000.0016Ω

3) Using ε = 30[V]sin(ωt), calculate the current in the circuit. This will be a function of time.

I(t) = \frac{ε}{Z} = \frac{30[V]sin(400[rad/s]t)}{20000.0016[Ω]} = \frac{30[V]sin(400[rad/s]t)}{20000.0016[Ω]} = 0.00149sin(400t)

So I(t) = 0.00149sin(400t)

4) Draw the phasor diagram for t=0 seconds.

I wasn't sure at all how to go about doing this one. As far as I can tell, this one ends up being a graph with voltage and current functions (current found in #3) drawn at t=0, showing how out of phase they are at that time, although I'm not sure how to find the voltage/what to use to find it. Of course, I don't want anyone to draw the graph for me, but some advice on phasor diagrams in general/a push in the right direction would be very nice.

Any help would be greatly appreciated. Thank you in advance!
 
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The capacitance is given in microfarads: C=250 *10-6 F. Repeat the calculations.

ehild
 
Alrighty. I guess my mind totally drew a blank around that capacitance. :blushing:

I feel a lot better about the frequency now; I'm hoping the others are okay, too.

1) Calculate the resonance frequency for this circuit.
ω_{o} = \frac{1}{\sqrt{LC}}
L = 20mH = 0.02H; C = 250x10^{-6}F
ω_{o} = \frac{1}{\sqrt{(0.02H)(250x10^{-6}F)}} = \frac{1}{.00223 sec} = 447.21 Hz

2) For a frequency ω=400 rad/s, determine the phase angle and the circuit impedance.
Phase Angle ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right]

X_{L} = ωL = (400)(0.02) = 8
X_{C} = \frac{1}{(400)(250x10^{-6})} = \frac{1}{.1} = 10
R = 20kΩ

ϕ = tan^{-1} \left[\frac{X_{L}-X_{C}}{R}\right] = tan^{-1} \left[\frac{8-10}{20,000}\right] = tan^{-1} \left[\frac{-2}{20,000}\right] = tan^{-1} \left[-1.0x10^{-4}\right] = -0.0057°

Impedance Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}} = \sqrt{20,000^{2} + (8 - 10)^{2}} = \sqrt{4.0x10^{8} + 4} = 20000.0001Ω

3) Using ε = 30[V]sin(ωt), calculate the current in the circuit. This will be a function of time.

I(t) = \frac{ε}{Z} = \frac{30[V]sin(400[rad/s]t)}{20000.0001[Ω]} = \frac{30[V]sin(400[rad/s]t)}{20000.0001[Ω]} = 0.0015sin(400t)

So I(t) = 0.0015sin(400t)

4) Draw the phasor diagram for t=0 seconds.
I'm still a little confused about this phasor diagram, but I think I can get by. Again, if anyone could offer a little advice on this, it would be great.

And thank you for catching my mistake, ehild.
 
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