What Is the Electric Field Perpendicular to a Uniformly Charged Rod?

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SUMMARY

The discussion focuses on calculating the electric field perpendicular to a uniformly charged rod with a length of 0.1m and a linear charge density of 3C/m. The correct approach involves using the principle of superposition and integrating the electric field contributions from differential elements along the rod. The integration should be performed using the formula 2λL∫(ddl/(L² + d²)^(3/2)), with limits from 0 to 0.05m (half the length of the rod) and λ representing the linear charge density.

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  • Understanding of electric fields and charge distributions
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of the principle of superposition in electrostatics
  • Basic concepts of linear charge density
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Homework Statement


A rod of length 0.1m has a uniform linear charge density of 3C/m. Determine the Electric field at a point d=P located at a perpendicular distance 1m along a line of symmetry of the rod.


The Attempt at a Solution


I know i have to use super position and integrate but I don't think I'm using the right integration.

I was trying 2[tex]\lambda[/tex]L[tex]\oint[/tex][tex]\frac{ddl}{ (L^2 + d^2)^3/2}[/tex]
 
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it should be (L^2 + d^2) to the 3/2 power. and it is integrated from 0 to 1/2. and lamba is the linear charge density, L is length of rod, d is distance normal to rod
 

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