CaptProton987
- 2
- 0
Circuit Analysis--Nodal error?
Find R_Load for maximum power that can be transferred to the load.
KCL@V1: (V1-6v)/3kΩ + (V1-V3)/6kΩ + (V1 - V2)/2kΩ - 2mA = 0
KCL@V2: 2mA + (V2 - V1)/2kΩ + Isc = 0
KCL@V3: 2mA + (V3-V1)/6kΩ - Isc = 0
NOTE: The above equations are currents for KCL that I came up with while attempting Nodal Analysis so they may be incorrect...
Okay basically I'm trying to do two things here:
(1) reduce the circuit to one voltage source and one resistor for Thevenin's theorem.
I've started by removing the load resistor, and trying to find the value for Isc [short circuit current] via nodal analysis... but I'm stuck I don't believe the above nodal equations are correct and even if they are I really! screwed up trying to solve for V1, V2, and V3.
(2) Once I have the Thev. equivalent circuit I want to plug that load resistor back in and find its value that will "Maximize power" -- I have absolutely no idea how to do this.
I've uploaded some images of the circuit I drew [software isn't working for me but at least it makes nice pictures] to give you an idea of what I'm doing...
Homework Statement
Find R_Load for maximum power that can be transferred to the load.
Homework Equations
KCL@V1: (V1-6v)/3kΩ + (V1-V3)/6kΩ + (V1 - V2)/2kΩ - 2mA = 0
KCL@V2: 2mA + (V2 - V1)/2kΩ + Isc = 0
KCL@V3: 2mA + (V3-V1)/6kΩ - Isc = 0
The Attempt at a Solution
NOTE: The above equations are currents for KCL that I came up with while attempting Nodal Analysis so they may be incorrect...
Okay basically I'm trying to do two things here:
(1) reduce the circuit to one voltage source and one resistor for Thevenin's theorem.
I've started by removing the load resistor, and trying to find the value for Isc [short circuit current] via nodal analysis... but I'm stuck I don't believe the above nodal equations are correct and even if they are I really! screwed up trying to solve for V1, V2, and V3.
(2) Once I have the Thev. equivalent circuit I want to plug that load resistor back in and find its value that will "Maximize power" -- I have absolutely no idea how to do this.
I've uploaded some images of the circuit I drew [software isn't working for me but at least it makes nice pictures] to give you an idea of what I'm doing...