What is the Pressure of a Gas in a Barometric Chamber?

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In the discussion about gas pressure in a barometric chamber, a problem is presented involving an ideal gas where the pressure increases by 10% and the volume by 20%. Participants explore how these changes affect temperature, with multiple-choice answers provided. Additionally, the scenario includes a barometer reading of 759 torr against standard atmospheric pressure, prompting calculations for the gas pressure in the chamber. The conversation reveals uncertainty about the correct application of gas laws to solve the problems posed. Overall, the thread highlights the complexities of gas behavior under changing conditions.
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Homework Statement



If the pressure of an ideal gass rises whit 10% and the volume by 20% , the temperature modifies by :
a. 35%
b. 5%
c. 10%
d. 30%
e. 32%

Homework Equations


i don't know :(



The Attempt at a Solution


:D idk
 
Physics news on Phys.org
One ideal gass is in normal conditions and its suffering a izobar transformations and the volume of the gass is rising by 25% from the initial value.The temperature which the gass will have is?
1.44,7 C
2. 426 K
3. 369 K
D. 68.3 C
E. 136.5 C
 
When the atmospheric pressure is 760 torr a barometer show 759 torr.The pressure of the gass found in a barometric chamber is?
1. 133.3 N/M^2
2. 20 torr
3. 12 torr
d. 850 N/M^2
e. 1.31 kN/m^2
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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