Engineering What is the voltage in the circuit?

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    Circuit Voltage
AI Thread Summary
The voltage in the circuit was initially calculated as V0 = 12.5292V, but after reviewing the equations, the correct voltage was determined to be +13.12V. The discussion involved both loop analysis and nodal equations, with one participant expressing a preference for nodal methods due to perceived complexities in loop equations. Errors were identified in the initial equations, particularly regarding the consideration of resistors. The participants collaborated to verify calculations and correct mistakes, ultimately arriving at the same voltage result. The thread emphasizes the importance of careful equation setup in circuit analysis.
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Homework Statement



http://i.imgur.com/YRK5L.png

Homework Equations



Loop analysis, so KVL

The Attempt at a Solution



I did the problem, and I got V0 = 12.5292V. If this is incorrect, I'll be more than happy to upload my work. Can someone verify the answer for me? Just tell me if it's right or wrong.
 
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I got Vo+ - Vo- = +14.359 V.

I use nodal equations rather than loop equations. I've always thought loop equations were stupid. I just pick every independent node and sum currents = 0. For example, my first (of three) equation is

(10 - Vx)/2K + (Vo+ - Vx)/3K + 8mA = 0.
Vx is the voltage in the middle. I made the bottom node zero V. (I really should have made Vo- = 0 but it doesn't matter).

I don't want to look at your loop equations, for which I apologize. I just don't like it when one component can carry 2 or 3 or even more "currents"!

BTW I used math app software to do the equation solving so my answer is correct assuming I wrote the equations right. I checked carefully but they could still be wrong, of course.
 
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It seems like your example nodal equation is for the middle node, in which case, I think it looks incorrect?

If it is the middle node, you forgot to consider the 2k resistor to the right of the node.
 
You are absolutely right!

I will recompute. Thanks for bringiong that to my attention.
 
Now I get +13.12V.

Here are my three equations, maybe you can spot another mistake. Don't be confused by the fact that I use conductances instead of resistances: G = 1/R. It makes the math easier for me. Conductances are in mS, currents in mA (1mS = 1/1K ohm):

0.5(10-x) + .33333(Vop-x) + 8 + 0.5(Von-x) = 0
4 = 0.33333(Vop-x) + 0.125(Vop-Von)
0.125(Vop-Von) + 0.5(x-Von) = 0.125Von
 
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rude man said:
Now I get +13.12V.

Here are my three equations, maybe you can spot another mistake. Don't be confused by the fact that I use conductances instead of resistances: G = 1/R. It makes the math easier for me. Conductances are in mS, currents in mA (1mS = 1/1K ohm):

0.5(10-x) + .33333(Vop-x) + 8 + 0.5(Von-x) = 0
4 = 0.33333(Vop-x) + 0.125(Vop-Von)
0.125(Vop-Von) + 0.5(x-Von) = 0.125Von

Awesome, I tried doing the problem again and it seemed like I missed something in my loop equations as well. I got 13.12 V too.
 
Could you possibly look at my other question please?

https://www.physicsforums.com/showthread.php?t=539166"

It uses loop analysis, which I know you said earlier that you dislike, but primarily I'd like to know if my answer is correct. Thanks.

In the best case scenario, you could maybe point out my error in my work. I put all of my equations in the post. Thanks again for your help on this problem!
 
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