gracy
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From where mg sin theta is coming?component of mg?
It is the resultant force on m. You know that it accelerates down the incline with a= gsin(37), so the resultant force is ma= mgsin(37).gracy said:From where mg sin theta is coming?component of mg?
ehild said:I see. Then my drawing was wrong, why did you say it was correct ?
ehild said:In physics problems, block is meant that : http://www.wdlconcrete.co.uk/images/blockmain-dense-midi.jpg
Yes, but a wedge was drawn, and the solution they provided counts with the wedge.gracy said:But the link I have provided says M is also a block.
You mean question is wrong?ehild said:Yes, but a wedge was drawn
How much time does it take to resolve a vector into two components, one horizontal and the other vertical?gracy said:Actually I am running out of time.
I have done this but not getting answer.Chestermiller said:How much time does it take to resolve a vector into two components, one horizontal and the other vertical?
Well tell us what you get for the two components of the acceleration.gracy said:I have done this but not getting answer.
I do not see that you gave the horizontal and vertical components of the force F=mgsin(37). Recall that force is parallel with the incline, so makes 37°angle with the horizontal.gracy said:I have done this but not getting answer.