Where Am I Going Wrong in Calculating Minimum Coefficient of Friction?

AI Thread Summary
The discussion revolves around calculating the minimum coefficient of friction required for a small block (m) to not slide on a larger block (M) on an incline. The key points include the need for static friction, as both blocks must accelerate together down the incline at g sin(θ). The user initially miscalculated the frictional forces and the role of gravity, leading to an incorrect conclusion about the coefficient of friction being less than 0.75 instead of the correct value. Participants emphasize the importance of drawing accurate free body diagrams to analyze the forces acting on the blocks. Ultimately, the correct approach involves recognizing that the force of static friction must balance the gravitational component acting on the smaller block along the incline.
  • #51
From where mg sin theta is coming?component of mg?
 
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  • #52
gracy said:
From where mg sin theta is coming?component of mg?
It is the resultant force on m. You know that it accelerates down the incline with a= gsin(37), so the resultant force is ma= mgsin(37).
 
  • #53
ehild said:
I see. Then my drawing was wrong, why did you say it was correct ?
ehild said:
In physics problems, block is meant that : http://www.wdlconcrete.co.uk/images/blockmain-dense-midi.jpg

But the link I have provided i.e http://www.educationguru4u.com/Pages/EasyPhysics.aspx says M is also a block.
 
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  • #54
gracy said:
But the link I have provided says M is also a block.
Yes, but a wedge was drawn, and the solution they provided counts with the wedge.
 
  • #55
ehild said:
Yes, but a wedge was drawn
You mean question is wrong?
 
  • #56
In wider meaning, block can mean other shapes.
a. A solid piece of a hard substance, such as wood, having one or more flat sides.
b.
Such a piece used as a construction member or as a support.
c. Such a piece upon which chopping or cutting is done: a butcher's block.
d. Such a piece upon which persons are beheaded.
e. One of a set of small wooden or plastic pieces, such as a cube, bar, or cylinder, used as a building toy.

So solve the problem according to the original figure. The top surface of M is horizontal, as in your second figure in the OP.
 
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  • #57
How your post 50 gives answer 0.75?Please answer.
 
  • #58
In PF it's good habit that we help as much as we can, but do not do the exercise for the poster. You wouldn't let someone else train in your place if you want to run a marathon, would you ?

So back to post #3 by Chet: three forces working on m have to result in an acceleration gsinθ g\sin\theta along the plane.
Draw the diagram (that's done now) and calculate the forces.
 
  • #59
I have done really hardwork on this particular question,that's why I was expecting that I will be understood that inspite of so much try she is not getting let's help her one step ahead by providing complete solution of the question..But no problem .
 
  • #60
Actually I am running out of time.
 
  • #61
gracy said:
Actually I am running out of time.
How much time does it take to resolve a vector into two components, one horizontal and the other vertical?

Chet
 
  • #62
Chestermiller said:
How much time does it take to resolve a vector into two components, one horizontal and the other vertical?
I have done this but not getting answer.
 
  • #63
gracy said:
I have done this but not getting answer.
Well tell us what you get for the two components of the acceleration.

Chet
 
  • #64
gracy said:
I have done this but not getting answer.
I do not see that you gave the horizontal and vertical components of the force F=mgsin(37). Recall that force is parallel with the incline, so makes 37°angle with the horizontal.
 
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