Why is my torque calculation incorrect for this simple force problem?

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The discussion revolves around a torque calculation issue related to a force problem. The user has resolved the forces into components but is struggling with the torque calculation using the cross product of the position vector and the force vector. Key corrections include ensuring the y-component of the force is negative and that the position vector should extend from the axis of rotation to the point of force application. Clarifications on the coordinates of points A, P, and M are also suggested to aid in the calculation. Properly addressing these aspects is essential for accurate torque computation.
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http://img403.imageshack.us/img403/879/problem4998tl.jpg

Here I resolved the forces:

\overrightarrow{F_{A_x}} = \left(375sin30\right)N

\overrightarrow{F_{A_y}} = \left(375cos30\right)N

Here is the r vector (I think):

\overrightarrow{r_{AP}} = \left(4\hat{i} - 3\hat{j}\right)m

But when I do r X F, I get something wrong, what do I have to do to solve this simple problem?
 
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Let the Centre of AP be M, then MP is the radius Vector I guess from what I understood after seeing the picture. You know the co-ordinate of A and P, so you can find the co-ordinates of M.
 
VinnyCee said:
http://img403.imageshack.us/img403/879/problem4998tl.jpg

Here I resolved the forces:

\overrightarrow{F_{A_x}} = \left(375sin30\right)N

\overrightarrow{F_{A_y}} = \left(375cos30\right)N

Here is the r vector (I think):

\overrightarrow{r_{AP}} = \left(4\hat{i} - 3\hat{j}\right)m

But when I do r X F, I get something wrong, what do I have to do to solve this simple problem?

The y component fo your force should be negative.
Also, in calculating the torque, the vector r should go from the axis of rotation toward the point where the force is applied.

Patrick
 
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