Covariant Definition and 345 Threads
-
K
I Covariant Derivatives: Doubt on Jolt & Proving Zj Γjk Vi = 0
I've just learned about the covariant derivatives (##\nabla_i## and ##\delta/\delta t##) and I have a doubt. We should be able to say that $$ J^i = \frac{\delta A^i}{\delta t} = \frac{\delta^2 V^i}{\delta^2 t} = \frac{\delta^3 Z^i}{\delta^3 t} $$ where ##J## is the jolt. This...- kiuhnm
- Thread
- Covariant Derivatives Tensor calculus
- Replies: 11
- Forum: Differential Geometry
-
D
I Transforming Contra & Covariant Vectors
Hi. The book I am using gives the following equations for the the Lorentz transformations of contravariant and covariant vectors x/μ = Λμν xν ( 1 ) xμ/ = Λμν xv ( 2 ) where the 2 Lorentz transformation matrices are the inverses of each other. I am trying to get equation 2...- dyn
- Thread
- Covariant Covariant vectors Vectors
- Replies: 12
- Forum: Special and General Relativity
-
I Do Isometries Preserve Covariant Derivatives?
O'Neill's Elementary Differential Geometry, in problem 3.4.5, asks the student to prove that isometries preserve covariant derivatives. Before solving the problem in general, I decided to work through the case where the isometry is a simple inversion: ##F(p)=-p##, using a couple of simple vector...- Gene Naden
- Thread
- Covariant Derivatives Differential geometry
- Replies: 14
- Forum: Differential Geometry
-
M
Covariant derivative summation convention help
Homework Statement Assume that you want to the derivative of a vector V with respect to a component Zk, the derivative is then ∂ViZi/∂Zk=Zi∂Vi/∂Zk+Vi∂Zi/∂Zk = Zi∂Vi/∂Zk+ViΓmikZm Now why is it that I can change m to i and i to j in ViΓmikZm?- Mathematicsresear
- Thread
- Convention Covariant Covariant derivative Derivative Summation
- Replies: 4
- Forum: Advanced Physics Homework Help
-
K
I Covariant Derivative Equivalence: Exploring an Intriguing Result
If we are representing the basis vectors as partial derivatives, then ##\frac{\partial}{\partial x^\nu + \Delta x^\nu} = \frac{\partial}{\partial x^\nu} + \Gamma^\sigma{}_{\mu \nu} \Delta x^\mu \frac{\partial}{\partial x^\sigma}## to first order in ##\Delta x##, correct? But in the same manner...- kent davidge
- Thread
- Covariant Covariant derivative Derivative Equivalence
- Replies: 4
- Forum: Special and General Relativity
-
I EoM via varying action - covariant derivative when integrate
##\int d^4 x \sqrt {g} ... ## if I am given an action like this , were the ##\sqrt{\pm g} ## , sign depending on the signature , is to keep the integral factor invariant, when finding an eom via variation of calculus, often one needs to integrate by parts. When you integrate by parts, with...- binbagsss
- Thread
- Covariant Covariant derivative Derivative Eom Integrate
- Replies: 12
- Forum: Special and General Relativity
-
K
I Comparing Lie & Covariant Derivatives of Vector Fields
I subtracted the ##\mu##-th component of the Lie Derivative of a Vector ##U## along a vector ##V## from the ##\mu##-th component of the Covariant derivative of the same vector ##U## along the same vector ##V## and I got ##(\nabla_V U)^\mu - (\mathcal{L}_V U)^\mu = U^\nu \partial_\nu V^\mu -...- kent davidge
- Thread
- Covariant Derivatives
- Replies: 2
- Forum: Special and General Relativity
-
I Deriving Covariant Form of $E_{1}E_{2}|\vec{v}|$
Given a two particle scattering problem with (initial) relative velocity $|\vec{v}|$, apparently the product $E_{1}$E_{2}|\mathb{v}|$ can be expressed in the covariant form: $$ E_{1}E_{2}|\vec{v}| = \sqrt{ (p_{1}\cdot p_{2} - m_{1}^{2}m_{2}^{2}} $$ My textbook gives no further explanation -...- bananabandana
- Thread
- Covariant Form Scattering Special relativity
- Replies: 3
- Forum: Special and General Relativity
-
Tensor Covariant Derivative Expressions Algebra (Fermi- Walk
Homework Statement Hi I am looking at part a). Homework Equations below The Attempt at a Solution I can follow the solution once I agree that ## A^u U_u =0 ##. However I don't understand this. So in terms of the notation ( ) brackets denote the symmetrized summation and the [ ] the...- binbagsss
- Thread
- Algebra Covariant Covariant derivative Derivative Expressions Fermi Tensor
- Replies: 7
- Forum: Calculus and Beyond Homework Help
-
P
B How Is the Gradient Covariant in Different Coordinate Systems?
Hi, basic cartesian coordinates and we want to know the gradient of a scalar function of x,y, and z. So we can use the most basic basis there is of three orthogonal unit vectors and come up with the gradient of the scalar function. Now without rescaling the coordinate system or altering it in...- plob
- Thread
- Covariant Gradient
- Replies: 7
- Forum: Linear and Abstract Algebra
-
P
A Compute Commutator of Covariant Derivative & D/ds on Vector Fields
Hi, let ##\gamma (\lambda, s)## be a family of geodesics, where ##s## is the parameter and ##\lambda## distinguishes between geodesics. Let furthermore ##Z^\nu = \partial_\lambda \gamma^\nu ## be a vector field and ##\nabla_\alpha Z^\mu := \partial_\alpha Z^\mu + \Gamma^\mu_{\:\: \nu \gamma}...- Pentaquark6
- Thread
- Commutator Covariant Covariant derivative Derivative Fields General relaivity Geodesics Vector Vector fields
- Replies: 5
- Forum: Special and General Relativity
-
A Prove EL Geodesic and Covariant Geodesic Defs are Same via Riemmanian Geometry
... via plugging in the Fundamental theorem of Riemmanian Geometry : ##\Gamma^u_{ab}=\frac{1}{2}g^{uc}(\partial_ag_{bc}+\partial_bg_{ca}-\partial_cg_{ab})## Expanding out the covariant definition gives the geodesic equation as: (1) ##\ddot{x^u}+\Gamma^u_{ab} x^a x^b =0 ## (2) Lagrangian is...- binbagsss
- Thread
- Covariant Geodesic
- Replies: 6
- Forum: Special and General Relativity
-
I Does a covariant version of Euler-Lagrange exist?
Hello everyone. I've seen the usual Euler-Lagrange equation for lagrangians that depend on a vector field and its first derivatives. In curved space the equation looks the same, you just replace the lagrangian density for {-g}½ times the lagrangian density. I noticed that you can replace...- JuanC97
- Thread
- Covariant Euler-lagrange
- Replies: 2
- Forum: Differential Geometry
-
I What is the covariant derivative of the position vector?
What is the covariant derivative of the position vector $\vec R$ in a general coordinate system? In which cases it is the same as the partial derivative ?- Alain De Vos
- Thread
- Covariant Covariant derivative Derivative Position Position vector Vector
- Replies: 6
- Forum: Differential Geometry
-
I Contravariant first index, covariant on second, Vice versa?
I am working through a derivation of the Dirac matrix transformation properties. I have a tensor for the Lorentz transformation that is covariant on the first index and contravariant on the second index. For the derivation, I need vice versa, i.e. covariant on the second index and contravariant...- Gene Naden
- Thread
- Contravariant Covariant Index
- Replies: 36
- Forum: Special and General Relativity
-
P
A Interpretation of covariant derivative of a vector field
On Riemannian manifolds ##\mathcal{M}## the covariant derivative can be used for parallel transport by using the Levi-Civita connection. That is Let ##\gamma(s)## be a smooth curve, and ##l_0 \in T_p\mathcal{M}## the tangent vector at ##\gamma(s_0)=p##. Then we can parallel transport ##l_0##...- Pentaquark5
- Thread
- Covariant Covariant derivative Derivative Field General relaivity Interpretation Null geodesics Vector Vector field
- Replies: 2
- Forum: Special and General Relativity
-
Covariant derivative and 'see-saw rule'
Homework Statement Apologies if this is a stupid question but just thinking about the see-saw rule applied to something like: ## w_v \nabla_u V^v = w^v \nabla_u V_v ## It is not obvious that the two are equivalent to me since one comes with a minus sign for the connection and one with a plus...- binbagsss
- Thread
- Covariant Covariant derivative Derivative
- Replies: 2
- Forum: Topology and Analysis
-
I Confirming Covariant Derivative in Hartle's Gravity
In Hartle's Gravity we have the covariant derivative (first in an LIF) which is: ##\nabla_{\beta} v^{\alpha} = \frac{\partial v^{\alpha}}{\partial x^{\beta}}## As the components of the tensor ##\bf{ t = \nabla v}##. But, it's not clear which components they are! My guess is that...- PeroK
- Thread
- Covariant Covariant derivative Derivative
- Replies: 10
- Forum: Special and General Relativity
-
F
I Covariant derivative of Ricci scalar causing me grief
Hi all I'm having trouble understanding what I'm missing here. Basically, if I write the Ricci scalar as the contracted Ricci tensor, then take the covariant derivative, I get something that disagrees with the Bianchi identity: \begin{align*} R&=g^{\mu\nu}R_{\mu\nu}\\ \Rightarrow \nabla...- ft_c
- Thread
- Covariant Covariant derivative Derivative Ricci scalar Scalar
- Replies: 4
- Forum: Differential Geometry
-
S
A Covariant derivative in Standard Model
The covariant derivative in standard model is given byDμ = ∂μ + igs Gaμ La + ig Wbμ Tb + ig'BμYwhere Gaμ are the eight gluon fields, Wbμ the three weak interaction bosons and Bμ the single hypercharge boson. The La's are SU(3)C generators (the 3×3 Gell-Mann matrices ½ λa for triplets, 0 for...- Shen712
- Thread
- Covariant Covariant derivative Derivative Model Standard Standard model
- Replies: 1
- Forum: High Energy, Nuclear, Particle Physics
-
T
I Finding Covariant and Contravariant components of Cylin Coor
I'm going through Introduction_to_Tensor_Calculus by Wiskundige_Ingenieurstechnieken. I want to find the covariant and contravariant components of the cylindrical cooridnates. Ingerniurstechnieken sets tangent vectors as basis (E1, E2, E3). He also sets the normal vectors as another basis (E1...- thusidie
- Thread
- Components Contravariant Covariant
- Replies: 3
- Forum: Special and General Relativity
-
A Covariant derivative only for tensor
Hi initially I am aware that christoffel symbols are not tensor so their covariant derivatives are meaningless, but my question is why do we have to use covariant derivative only with tensors? ?? Is there a logic of this situation? ?- mertcan
- Thread
- Covariant Covariant derivative Derivative Tensor
- Replies: 3
- Forum: Differential Geometry
-
I Problem with Commutator of Gauge Covariant Derivatives?
Hi there, I have just read that the gauge field term Fμν is proportional to the commutator of covariant derivatives [Dμ,Dν]. However, when I try to calculate this commatator, taking the symmetry group to be U(1), I get the following: \left[ { D }_{ \mu },{ D }_{ \nu } \right] =\left( {...- tomdodd4598
- Thread
- Commutator Covariant Covariant derivative Derivatives Gauge Gauge theory
- Replies: 8
- Forum: Quantum Physics
-
A Understanding the Dual Basis and Its Directions
Please help. I do understand the representation of a vector as: vi∂xi I also understand the representation of a vector as: vidxi So far, so good. I do understand that when the basis transforms covariantly, the coordinates transform contravariantly, and v.v., etc. Then, I study this thing...- JTC
- Thread
- Basis Contravariant Covariant Dual Dual basis Gradient Metric
- Replies: 9
- Forum: Differential Geometry
-
I Solving Covariant Derivatives: Minkowskian Metric
How does one solve a problem like this? Suppose we have $$(e_\theta + f(\theta)e_\varphi) (e_\theta + f(\theta)e_\varphi)$$ What is the result of the above operation? As I remember it from the theory of covariant derivatives, the above relation would look like this $$e_\theta[e_\theta] +...- davidge
- Thread
- Covariant Derivatives
- Replies: 17
- Forum: Special and General Relativity
-
I Transformation of covariant vector components
Riley Hobson and Bence define covariant and contravariant bases in the following fashion for a position vector $$\textbf{r}(u_1, u_2, u_3)$$: $$\textbf{e}_i = \frac{\partial \textbf{r}}{\partial u^{i}} $$ And $$ \textbf{e}^i = \nabla u^{i} $$ In the primed...- saadhusayn
- Thread
- Components Covariant Covariant vectors Tensor analysis Transformation Vector Vector components
- Replies: 1
- Forum: Differential Geometry
-
General relativity, geodesic, KVF, chain rule covariant derivatives
Homework Statement To show that ##K=V^uK_u## is conserved along an affinely parameterised geodesic with ##V^u## the tangent vector to some affinely parameterised geodesic and ##K_u## a killing vector field satisfying ##\nabla_a K_b+\nabla_b K_a=0## Homework Equations see above The Attempt at...- binbagsss
- Thread
- Chain Chain rule Covariant Derivatives General General relativity Geodesic Relativity
- Replies: 2
- Forum: Calculus and Beyond Homework Help
-
J
A Evaluate Covariant Derivative on Tensors
Hello there, Recently I encountered a type of covariant derivative problem that I never before encountered: $$ \nabla_\mu (k^\sigma \partial_\sigma l_\nu) $$ My goal: to evaluate this term According to Carroll, the covariant derivative statisfies ##\nabla_\mu ({T^\lambda}_{\lambda \rho}) =...- Jonsson
- Thread
- Covariant Covariant derivative Derivative Tensors
- Replies: 7
- Forum: Special and General Relativity
-
P
I Product rule for exterior covariant derivative
It is well known that the product rule for the exterior derivative reads d(a\wedge b)=(da)\wedge b +(-1)^p a\wedge (db),where a is a p-form. In gauge theory we then introduce the exterior covariant derivative D=d+A\wedge. What is then D(a ∧ b) and how do you prove it? I obtain D(a\wedge...- Physics_Stuff
- Thread
- Covariant Covariant derivative Derivative Product Product rule
- Replies: 2
- Forum: Differential Geometry
-
P
I Differential forms as a basis for covariant antisym. tensors
In a text I am reading (that I unfortunately can't find online) it says: "[...] differential forms should be thought of as the basis of the vector space of totally antisymmetric covariant tensors. Changing the usual basis dx^{\mu_1} \otimes ... \otimes dx^{\mu_n} with dx^{\mu_1} \wedge ...- Physics_Stuff
- Thread
- Basis Covariant Differential Differential forms Forms Tensors
- Replies: 1
- Forum: Other Physics Topics
-
I Worked example on a covariant vector transformation
Hello. I would like to check my understanding of how you transform the covariant coordinates of a vector between two bases. I worked a simple example in the attached word document. Let me know what you think.- Dyatlov
- Thread
- Covariant Covariant vectors Example Transformation Vector
- Replies: 4
- Forum: Differential Geometry
-
Covariant Derivative Homework: Solve ∇_c ({∂}_b X^a)
Homework Statement Take the Covariant Derivative ∇_{c} ({∂}_b X^a) Homework Equations ∇_{c} (X^a) = ∂_c X^a + Γ_{bc}^a X^b ∇_{c} (X^a_b) = ∂_c X^a_b + Γ_{dc}^a X^d_b - Γ^d_{bc} X^a_d The Attempt at a Solution Looking straight at ∇_{c} ({∂}_b X^a) I'm seeing two indices. However, the b is...- MattRob
- Thread
- Covariant Covariant derivative Derivative
- Replies: 2
- Forum: Advanced Physics Homework Help
-
O
A What Are the Different Types of Derivatives in Calculus?
Derivatives in first year calculus Gateaux Derivatives Frechet Derivatives Covariant Derivatives Lie Derivatives Exterior Derivatives Material Derivatives So, I learn about Gateaux and Frechet when studying calculus of variations I learn about Covariant, Lie and Exterior when studying calculus... -
J
Books on Covariant formulation of Electrodynamics
Hello! I am an undergraduate currently enrolled in a course on theoretical physics. One big part of the course is on the classical field theory of electromagnetism(on its covariant formulation using Lagrangians mostly). So, I would like to ask which are some good books on the subject. Thanks in...- Joker93
- Thread
- Books Covariant Electrodynamics
- Replies: 3
- Forum: Electromagnetism
-
M
B Are All Quantum Gravity Theories Based on Covariant Quantum Fields?
I just read Carlo Rovelli new book "Reality is Not What It Seems: The Journey to Quantum Gravity" in one sitting. I'd like to know about the following: "Fields that live on themselves, without the need of a spacetime to serve as a substratum, as a support, and which are capable by themselves of...- mieral
- Thread
- Covariant Fields Quantum Quantum fields
- Replies: 14
- Forum: Beyond the Standard Models
-
Different versions of covariant Maxwell's equations
The standard way of writing Maxwell's equations is by assuming a vector potential ## A^\mu ## and then defining ## F_{\mu \nu}=\partial_\mu A_\nu-\partial_\nu A_\mu ##. Then by considering the action ## \displaystyle \mathcal S=-\int d^4 x \left[ \frac 1 {16 \pi} F_{\mu \nu}F^{\mu\nu}+\frac 1 c...- ShayanJ
- Thread
- Covariant Maxwell's equations
- Replies: 1
- Forum: Electromagnetism
-
D
I Covariant derivative of field strength tensor
Hi, I am struggling to derive the relations on the right hand column of eq.(4) in https://arxiv.org/pdf/1008.4884.pdfEven the easy abelian one (third row) which is $$D_\rho B_{\mu\nu}=\partial_\rho B_{\mu\nu}$$ doesn't match my calculation Since $$D_\rho B_{\mu\nu}=(\partial_\rho+i g...- d8586
- Thread
- Covariant Covariant derivative Derivative Field Field strength Gauge invariance Strength Tensor
- Replies: 2
- Forum: High Energy, Nuclear, Particle Physics
-
S
A What is the true definition of the covariant gamma matrix ##\gamma_{5}##?
Covariant gamma matrices are defined by $$\gamma_{\mu}=\eta_{\mu\nu}\gamma^{\nu}=\{\gamma^{0},-\gamma^{1},-\gamma^{2},-\gamma^{3}\}.$$ -----------------------------------------------------------------------------------------------------------------------------------------------------------...- spaghetti3451
- Thread
- Covariant Gamma Gamma matrices Matrices
- Replies: 7
- Forum: Quantum Physics
-
G
Different formulations of the covariant EM Lagrangian
Homework Statement I'm reading through A. Zee's "Quantum Field Theory in a nutshell" for personal learning and am a bit confused about a passage he goes through when discussing field theory for the electromagnetic field. I am well versed in non relativistic quantum mechanics but have no...- Gan_HOPE326
- Thread
- Covariant Covariant vectors Electromagetic field Em Lagrangian Qft Relativity
- Replies: 6
- Forum: Advanced Physics Homework Help
-
Covariant Derivatives (1st, 2nd) of a Scalar Field
Homework Statement Suppose we have a covariant derivative of covariant derivative of a scalar field. My lecturer said that it should be equal to zero. but I seem to not get it Homework Equations Suppose we have $$X^{AB} = \nabla^A \phi \nabla^B \phi - \frac{1}{2} g^{AB} \nabla_C \phi \nabla^C...- rezkyputra
- Thread
- Covariant Covariant derivative Derivatives Field General relativity Scalar Scalar field Tensor
- Replies: 3
- Forum: Advanced Physics Homework Help
-
I Commutator of covariant derivatives
Hi there I came across this paper. the author defines a covariant derivative in (1.3) ##D_\mu = \partial_\mu - ig A_\mu## He defines in (1.6) ##F_{jk} = i/g [D_j,D_k]## Why is it equal to ##\partial_j A_k - \partial_k A_j - ig [A_j, A_k]##? I suppose that it comes from a property of Lie...- naima
- Thread
- Commutator Covariant Derivatives
- Replies: 5
- Forum: Differential Geometry
-
S
A Gauge invariance and covariant derivative
Consider the covariant derivative ##D_{\mu}=\partial_{\mu}+ieA_{\mu}## of scalar QED. I understand that ##D_{\mu}\phi## is invariant under the simultaneous phase rotation ##\phi \rightarrow e^{i\Lambda}\phi## of the field ##\phi## and the gauge transformation ##A_{\mu}\rightarrow...- spaghetti3451
- Thread
- Covariant Covariant derivative Derivative Gauge Gauge invariance Invariance
- Replies: 1
- Forum: Quantum Physics
-
M
I Trying to understand covariant tensor
I am taking a course on GR and trying to understand Tensor calculus. I think I understand contravariant tensor (transformation of objects such as a vector from one frame to another) but I am having a hard time with covariant tensors. I looked into the Wikipedia page...- member 606890
- Thread
- Covariant Covariant derivative Covariant vectors Tensor Tensor calculus
- Replies: 5
- Forum: Special and General Relativity
-
S
Manifestly covariant Maxwell's equations
Consider the following Maxwell's equation in tensor notation: ##\partial_{k}F_{ij}=0## ##-\partial_{k}\epsilon_{ijm}B_{m}=0## ##\partial_{k}\epsilon_{ijm}B_{m}=0## ##\partial_{k}B_{k}=0## I wonder how you go from the third line to the fourth line.- spaghetti3451
- Thread
- Covariant Maxwell's equations
- Replies: 20
- Forum: Electromagnetism
-
I Covariant and contravariat components
hi, Initially I would like to ask a little and basic question: I know that $$v=\sum_{i=0} e_i v^i$$ where $$v^i=e^i v$$ But sometimes I think we can write the first equation like $$v=\sum_{i=0} e_i e^i v$$, and I am aware that $$e_i e^i=1$$ , then our equation becomes $$v=\sum_{i=0} v$$, ın...- mertcan
- Thread
- Components Covariant
- Replies: 2
- Forum: Differential Geometry
-
A Help with covariant differentiation
I'm having trouble evaluating the following expression (LATEX): ##\nabla_{i}\nabla_{j}T^{k}= \nabla_{i} \frac{\delta T^{k}}{\delta z^{j}} + \Gamma^{k}_{i m} \frac{\delta T^{m}}{\delta z^{i}} + \Gamma^{k}_{i m} \Gamma^{m}_{i l} T^{l}## What are the next steps to complete the covariant... -
A Expansion of covariant derivative
(V(s)_{||})^\mu = V(s)^\mu + s \Gamma^\mu_{\nu \lambda} \frac{dx^\nu}{ds} V(s)^\lambda + higher-order terms (Here we have parallel transported vector from point "s" to a very close point)Hi, I tried to make some calculations to reach the high-order terms for parallel transporting of vector...- mertcan
- Thread
- Covariant Covariant derivative Derivative Expansion
- Replies: 2
- Forum: Differential Geometry
-
A Riemann tensor and covariant derivative
hi, I tried to take the covariant derivative of riemann tensor using christoffel symbols, but it is such a long equation that I have always been mixing up something. So, Could you share the entire solution, pdf file, or links with me? ((( I know this is the long way to derive the einstein...- mertcan
- Thread
- Covariant Covariant derivative Derivative Riemann Riemann tensor Tensor
- Replies: 5
- Forum: Differential Geometry
-
I Covariant derivative of a contravariant vector
This is (should be) a simple question, but I'm lost on a negative sign. So you have ##D_m V_n = \partial_m V_n - \Gamma_{mn}^t V_t## with D_m the covariant derivative. When trying to deduce the rule for a contravariant vector, however, apparently you end up with a plus sign on the gamma, and I'm...- BiGyElLoWhAt
- Thread
- Contravariant Covariant Covariant derivative Derivative Derivatives Vector
- Replies: 35
- Forum: Differential Geometry
-
G
I Raising index on covariant derivative operator?
In Carroll, the author states: \nabla^{\mu}R_{\rho\mu}=\frac{1}{2} \nabla_{\rho}R and he says "notice that, unlike the partial derivative, it makes sense to raise an index on the covariant derivative, due to metric compatibility." I'm not seeing this very clearly :s What's the reasoning...- guitarphysics
- Thread
- Covariant Covariant derivative Derivative General relativity Index Operator
- Replies: 15
- Forum: Special and General Relativity