I discovered the following general solution to primitive forms of y^2 + 2x^2 = a^2
a = 3 + 4n(n+1)
y = 4n(n+1) - 1
x = 4n + 2
Moreover let P = {11, 17, 19, 41, 43 ...} = the set of prime divisors of numbers of the form 3+4n(n+1) without the 3, and let Q = { -1, 7, 17, 23 ...} = the set of...