An object falling from some point in the air (near the surface) with air friction, R = kv.
So,
m\frac{dv}{dt} = mg - kv
Seperate variables for
\int \frac{m}{mg - kv} \cdot dv = \int dt
and for the LHS I use integration by parts, so,
(m)(mgv - \frac{1}{2}kv^2) - \int mgv - \frac{1}{2}kv^2...