Calculate Bending Moment & Stress of Axle w/ 300N Load

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To calculate the bending moment at the center of an axle under a 300N load, the moment equation can be formed by using equilibrium conditions along the vertical axis. The bending moment can be expressed as M = F * distance, where the distance is measured from the load to the point of interest. The limit stress can be determined using the formula σ = M / W, where W is the section modulus, calculated as W = π(d^3) / 32 for a solid axle. To find the diameter of the axle, the bending moment and allowable stress values must be referenced from material strength data tables, considering safety factors. Proper calculations and assumptions are crucial for accurate results in mechanical design.
teng125
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Calculate the bending moment in the centre of the axle??
What limit stress is valid for this loading case ?

may i know how to form the moment eqn??
F=300N

picture - http://files.filefront.com//;5410274;;/

pls help
thanx
 
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What do you think? Try to form the equation on your own and we will inspect it.
 
i have try it many times but i don't know.
if in mechanics,this have to use the heaviside function,but this is machine design.therefore ,i don't know what to use.

i assume it is F(1) <x-175>^0 + F(1)<x-825^0>...
but i think this is incorrect
 
Well, heaviside functions aren't needed here.

Step 1: Determine the value of F_{1} using equilibrium condition along the vertical (y-axis).

Step 2: By considering half part of the rotating machine (cut machine into two at the centre), write down the bending moment equation of either side using \sum\vec{F}l=\vec{M_{b}}. It will be the same for the other half since it is symmetrical.
 
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if i cut into the half,then i'll get F * 325mm = M(b) rite??am i correct??

if it is correct,in order to find limit stress = bending moment / W , where W= pi (d^3) / 64 right??
how can i find the diameter and which shaft should i consider??
 
Bending_Moment.jpg


Your answer isn't correct. Try writing down the moment at C. Then we discuss the rest of the question.
 
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then it should be M + (F1*325) - (1/2F * 500) =0 right??am i correct??

if it is correct,in order to find limit stress = bending moment / W , where W= pi (d^3) / 64 right??
how can i find the diameter and which shaft should i consider??
 
Bingo.

How did you obtain the W? The correct axial section modulus W is W=\frac{\pi*d^3}{32}, assuming that the cross section of the axle is not hollow.

Setting \sigma_{all}=\frac{\sigma_{lim}}{n_{s}}=\frac{M_{b}}{W_{by}} and solve for the diameter d as you have found M_{b} in the first part, \sigma_{lim} can be found in a strength data table, depending on the material given and the safety factor should be, well, leave the diameter in terms of n_{s} if it isn't stated.
 
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ok...thanx...pls help me in the other question in the engineering side...thanx
 
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