Changing from cartesian to polar

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    Cartesian Polar
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The discussion focuses on converting a particle's motion from Cartesian to polar coordinates to find tangential and normal acceleration as functions of time. The particle's position is defined by specific equations for x(t) and y(t), leading to the need for second derivatives to determine acceleration. The user has calculated the velocity and acceleration components for both x and y but seeks to express these in polar coordinates to derive the tangential (a_t) and normal (a_n) accelerations. Clarification is needed regarding the notation used for alpha in the equations. The goal is to accurately compute a_t and a_n based on the derived polar expressions.
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Homework Statement


A particle moves in a two-dimensional orbit defined by:
x(t)= A(2\alphat-sin(\alphat)
y(t)= A(1-cos(\alphat)
a) Find the tangential acceleration a_t and normal acceleration a_n as a function of time where the tangential and normal components are taken with respect to the velocity.


Homework Equations


x''(t)= A\alpha^2sin(\alphat)
y''(t)= A\alpha^2cos(\alphat)


The Attempt at a Solution


I found both the velocity and acceleration for both x and y vectors given and realize that a(t)= x''(t)i\widehat{}+ y''(t)j\widehat{}
also I know that:
a(t)=a_nr\widehat{}+a_t\phi\widehat{}
So I need to find x" and y" in terms of polar to get the answe for a_n and a_t
 
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sorry all these alphas are not supposed to be raised to the power of there previous components. it is supposed to be for example x(t)=A(2*(alpha)*t-sin((alpha)*t)...and so on
 
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