The discussion revolves around the comparison of light bulbs connected in series versus parallel configurations, specifically focusing on their brightness and power consumption when connected to the same battery.
Some participants have provided insights into the power equations and how voltage and current behave in different circuit configurations. There is an acknowledgment of the reasoning behind why bulbs connected in parallel may be brighter, but the discussion remains open without a definitive conclusion.
Participants are considering the implications of constant resistance in the bulbs and how this affects the distribution of voltage and current in series versus parallel setups. There is an emphasis on understanding the underlying principles rather than reaching a final answer.
So we can write P=U^2/Rgneill said:In a very simple view, the brightness of a light bulb is proportional to the power it consumes. The power is determined by the voltage across the bulb and the current through it: ##P = V I##.
If you assume that the bulb has a constant resistance (again, a simple view), then Ohm's Law tells you that the current through it is related to the voltage across it by ##I = V/R##.
Use your knowledge of how voltage and current are distributed among components in series and parallel circuits.
Yes, that's a correct analysis.prishila said:So we can write P=U^2/R
U is the same in each resistance in parallel, but it divides in resistances in series. So it is greater in resistances in parallel. This way P is greater when they are connected in parallel. Am I right?