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E Cell Values!

  1. Nov 9, 2007 #1
    1. Using tabulated standard reduction potentials from your text, calculate the standard cell potential, E°cell (always positive for a galvanic cell), based on the following (unbalanced) reaction:

    IO3-(aq) + Fe2+(aq) --> Fe3+(aq) + I2(s)


    3.

    well you see i made the half reactions

    Fe3+ (aq) ---> Fe2+(aq) EØ was easily found +0.77 V

    IO3-(aq) ---> I2(s)


    balanced the 2nd one to

    12 H + 2IO3 + 5e- ---> I2 + 6H2O
    E CELL = ???????

    I CANT FIND THIS REACTION'S ECELL IN MY TEXT BOOK BUT SOMEHOW I FOUND IT ON THIS WEBSITE TO BE EØ = +1.19V, HOW DID THEY GET THIS VALUE!! PLEASE HELP
     
  2. jcsd
  3. Nov 10, 2007 #2
    any idea anyone??
     
  4. Nov 10, 2007 #3
    ok, first let's clear up any confusion

    is it ...

    [tex]IO_{3}^{-}(aq)\rightarrow I_{2}(s)[/tex]
     
  5. Nov 10, 2007 #4
    all they simply did was, balance out the equation with (first) H2O on the product side, then H+ on the reactant side

    i do not have my Chemistry book with me atm, so i cannot give you an in-depth explanation.
     
  6. Nov 11, 2007 #5
    yes i know how they balanced it but i dont understand how they got that Ecell value. In a table for example here

    http://en.wikipedia.org/wiki/Table_of_standard_electrode_potentials

    that reaction

    12 H + 2IO3 + 5e- ---> I2 + 6H2O

    is not there so how did they get the ecell value for it?
     
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