E&M Question -- Maxwell's Equation in matter reduce to Maxwell's equation in a vacuum....

  • #1
ParticleGinger6
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New user has been reminded to show their work on schoolwork questions
Homework Statement:
Maxwell's Equation in matter reduces to Maxwell's equation in vacuum if polarization and magnetization are zero?
Relevant Equations:
They can be found in the attached photo
I do not know where to start.
 

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Answers and Replies

  • #2
robphy
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How are polarization (i.e. the Polarization Vector Field) and magnetization (i.e. Magnetization Vector Field)\\ related to the vector fields [itex] \vec D [/itex] , [itex] \vec E [/itex], [itex] \vec B [/itex], and [itex] \vec H [/itex]?
 
  • #3
ParticleGinger6
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@robphy so i found the equations D = epsilon*E and H = (1/mu)*H where epsilon = epsilon(not)*(1+Xe) and mu = mu(not)*(1+Xe). I think if I use that convert D into terms of P which would look like P = D - epsilon(not)*E and H = B/(mu(not)*(1+Xe)). From there you can get Magnetization from M = Xm*H

Am I on the right track
 
  • #4
robphy
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Yes... but use [itex] \epsilon_0[/itex] and [itex] \mu_0[/itex] instead of the [itex] \chi[/itex]s.
 
  • #5
ParticleGinger6
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@robphy I believe I figured it out. So by using D = epsilon(not)E + P and H = B/mu(not) - M I was able to get to
dell * E = rou/epsilon(not) and dell cross B = mu(not)*J + mu(not)*epsilon(not)*(curly(d)*E/curly(d)t) for part a
Then for part b
I used P = epsilon(not)*X*E to get dell*E = rou/epsilon(not)
I used M = Xm*H to get dell cross B = mu(not)*J + mu(not)*epsilon(not)*(curly(d)*E/curly(d)t)
Both assuming mu approaches mu(not) and epsilon approaches epsilon(not)
 

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