How are polarization (i.e. the Polarization Vector Field) and magnetization (i.e. Magnetization Vector Field)\\ related to the vector fields [itex] \vec D [/itex] , [itex] \vec E [/itex], [itex] \vec B [/itex], and [itex] \vec H [/itex]?
#3
ParticleGinger6
32
5
@robphy so i found the equations D = epsilon*E and H = (1/mu)*H where epsilon = epsilon(not)*(1+Xe) and mu = mu(not)*(1+Xe). I think if I use that convert D into terms of P which would look like P = D - epsilon(not)*E and H = B/(mu(not)*(1+Xe)). From there you can get Magnetization from M = Xm*H
Yes... but use [itex] \epsilon_0[/itex] and [itex] \mu_0[/itex] instead of the [itex] \chi[/itex]s.
#5
ParticleGinger6
32
5
@robphy I believe I figured it out. So by using D = epsilon(not)E + P and H = B/mu(not) - M I was able to get to
dell * E = rou/epsilon(not) and dell cross B = mu(not)*J + mu(not)*epsilon(not)*(curly(d)*E/curly(d)t) for part a
Then for part b
I used P = epsilon(not)*X*E to get dell*E = rou/epsilon(not)
I used M = Xm*H to get dell cross B = mu(not)*J + mu(not)*epsilon(not)*(curly(d)*E/curly(d)t)
Both assuming mu approaches mu(not) and epsilon approaches epsilon(not)