Electric fields created by charged particles

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SUMMARY

The discussion focuses on calculating electric fields generated by charged particles, specifically three small charged balls: Q1 = 1 nC, Q2 = 5 nC, and Q3 = -2 nC. The electric field at the location of Q1 due to Q2 is calculated as <0, 1125, 0> N/C, while the field due to Q3 is <300, 0, 0> N/C. Additionally, the electric fields at location A due to each charge are computed, resulting in vector values of <300, 0, 0>, <540, 720, 0>, and <0, -450, 0> respectively. The discussion emphasizes the importance of using the correct formula, E = kq/r², and maintaining consistency in the coordinate system.

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Familiarity with vector mathematics
  • Knowledge of SI units, particularly nanocoulombs (nC)
  • Basic principles of electrostatics and forces on charged particles
NEXT STEPS
  • Study the application of Coulomb's law in different configurations of charged particles
  • Learn about vector addition in electric fields
  • Explore the concept of electric field lines and their representation
  • Investigate the behavior of charged particles in electric fields, including forces and motion
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Students studying physics, particularly those focusing on electromagnetism, as well as educators and anyone interested in understanding the principles of electric fields and forces on charged particles.

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Homework Statement



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At a particular moment, three small charged balls, one negative and two positive,are located as shown in Figure 13.46. Q1 = 1 nC, Q2 = 5 nC, and Q3 = -2 nC.

Remember that you must first convert all quantities to S.I. units. 1 nC = 1 nanocoulomb = 1e-9 C.

(a1) What is the electric field at the location of Q1, due to Q2?
(a2) What is the electric field at the location of Q1, due to Q3?


(c1) What is the electric field at location A, due to Q1?
(c2) What is the electric field at location A, due to Q2?
(c3) What is the electric field at location A, due to Q3?

(d) An alpha particle (He2+, containing two protons and two neutrons) is released from rest at location A. At the instant the particle is released, what is the electric force on the alpha particle, due to Q1, Q2 and Q3?

Homework Equations



|E|= kq/|r^2|

The Attempt at a Solution



(a1) (9e^9)(5x10^-9)/(.0016) *<0,.04,0>= <0,1125,0>
(a2) (9e^9)(-2x10^-9)/(.0009) * <.03,0,0>=<300,0,0>

(c1) (9e^9)(1x10^-9)/(.0009)* <.03,0,0>=<300,0,0>
(c2) (9e^9)(5x 10^-9)/(.0025)* <.03,.04,0>=<540,720,0>
(c3) (9e^9)(-2x 10^-9)/(.0016)* <0,.04,0)=<0,-450,0>
 
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The equation you need here is E = \frac{kq}{r^2} * \hat{r}, where k is the permitivity of free space.

\hat{r} represents the radial unit vector from the point charge to the point where you are calculating the electric field, and shouldn't have a magnitude. (I think your * < x,y,z> is indicating that you're multiplying by a magnitude, which would be incorrect).

Also, since this is a vector field, use their coordinate system and stay consistent.
 
Last edited:

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