Electrostatics - calculation of electric field intensity

AI Thread Summary
The discussion focuses on calculating electric field intensity at a point P, where a test charge qo is placed at a distance r from a source charge q. It emphasizes the importance of using a very small test charge to avoid altering the electric field due to its own influence, as indicated by the limit of qo tending to zero in Coulomb's law. The conversation highlights that this approach allows for accurate measurement of the electric field strength, particularly around charged bodies like metal spheres, which behave like point charges at their center. Participants clarify that a small qo ensures minimal interaction with the field, preserving the integrity of the measurement. This method is essential for understanding electrostatics and accurately calculating electric field intensity.
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electrostatics --- calculation of electric field intensity

Homework Statement


My aim is to calculate electric field intensity at a point P where the test charge qo is kept which is at a distance r from the source charge q is kept.


Homework Equations



Why it has mentioned limit qo tends to zero is mentioned in coulomb's law in my attached image?

The Attempt at a Solution


 

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We define the electric field around a charged body by putting a test charge qo at a certain distance and measure the electric force acting on it. But the additional charge will modify the field. In case when the "fixed charge" is distributed on a metal sphere, even the charge distribution can change. That is why we need to use a very small test charge. The influence of the test charge is less and less as qo tends to zero and we take the electric field strength as the force acting on the test charge at that limit. If we apply this definition, the field around a charged metal sphere is the same as that of a point charge placed in the centre.

ehild
 


Thanks for the reply ehild
 


It tends to zero so that its magnitude is such that it does not affect the field by polarizing or attracting other charges.
 


Thanks ashishsinghal for the clarification
 
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