Finding equivalent resistance in complex circuit

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SUMMARY

The discussion focuses on calculating the equivalent resistance of a modified Wheatstone bridge circuit with additional resistors. Participants emphasize that traditional series and parallel methods are ineffective due to the complexity introduced by the extra resistors. Instead, they recommend applying Kirchhoff's rules for accurate analysis. This approach is essential for solving circuits that cannot be simplified through standard methods.

PREREQUISITES
  • Understanding of Wheatstone bridge circuits
  • Familiarity with Kirchhoff's voltage and current laws
  • Basic knowledge of series and parallel resistor combinations
  • Ability to analyze complex electrical circuits
NEXT STEPS
  • Study Kirchhoff's laws in detail for circuit analysis
  • Practice finding equivalent resistance in complex circuits
  • Explore advanced circuit simulation tools like LTspice
  • Learn about mesh and nodal analysis techniques
USEFUL FOR

Electrical engineering students, circuit designers, and hobbyists interested in advanced circuit analysis techniques.

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In my previous question , situated here, I asked about finding the equivalent resistance of the following circuit :
5EMUd.png


I got some very good answers and some tips. Now what if the same circuit is modified by adding two more resistors on the free connecting wires like this :
attachment.php?attachmentid=62397&stc=1&d=1380724111.png


How should I find the equivalent resistance now ?
I probably can't redraw the circuit as mentioned in answers to my previous question since every wire has a resistor on it.
 

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That's a Wheatstone bridge. It cannot be solved by either parallel or series methods. You must use Kirchhoff's rules
 

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