Finding equivalent resistance in complex circuit

  • Thread starter agoogler
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  • #1
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In my previous question , situated here, I asked about finding the equivalent resistance of the following circuit :
5EMUd.png


I got some very good answers and some tips. Now what if the same circuit is modified by adding two more resistors on the free connecting wires like this :
attachment.php?attachmentid=62397&stc=1&d=1380724111.png


How should I find the equivalent resistance now ?
I probably can't redraw the circuit as mentioned in answers to my previous question since every wire has a resistor on it.
 

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  • #2
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That's a Wheatstone bridge. It cannot be solved by either parallel or series methods. You must use Kirchhoff's rules
 

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