Finding equivalent resistance in complex circuit

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agoogler
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In my previous question , situated here, I asked about finding the equivalent resistance of the following circuit :
Circuit schematic between terminals A and B with three resistors R1, R2 and R3 in series along a horizontal wire; a wire arcs over R1 and R2 and another wire arcs under R2 and R3.


I got some very good answers and some tips. Now what if the same circuit is modified by adding two more resistors on the free connecting wires like this :
Circuit schematic between terminals A and B with resistors R1, R2, R3, R4 (bridging over R1 and R2) and R5 (bridging under R2 and R3) arranged in a bridge-like configuration.


How should I find the equivalent resistance now ?
I probably can't redraw the circuit as mentioned in answers to my previous question since every wire has a resistor on it.
 
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  • Hand-drawn circuit schematic between terminals A and B: R1, R2 and R3 in series along the main wire, with R4 bridging from the left node above them to the right node, and R5 bridging from below R1 to the node after R2.
    res2.png
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That's a Wheatstone bridge. It cannot be solved by either parallel or series methods. You must use Kirchhoff's rules