# Frequency difference in two springs with different stiffness factors

1. Sep 16, 2009

### mhmil

1. The problem statement, all variables and given/known data

Your niece is working on a unique science fair project - a clock built around a small mass vibrating on a little spring. Her prototype version is working ok, but it's running too slow. Given your experience in this course, you suggest to her that a stiffer spring should oscillate faster, so she goes out and finds a new one with stiffness constant ("K") that is a factor 2.2 times larger than the prototype spring. How many times larger is the frequency of the new version than the old one? (If you think the new frequency is 2 times the old one, enter 2.0)

2. Relevant equations

This is where the problem is lying for me. I'm attempting to use F = 1/2pi*square root of K/M. I'm unable to find the numbers to complete the K/M at all in this question.

3. The attempt at a solution

F= (1/2pi)=(.159)
(.159)*Square root of K/M

I cannot figure out what K and M should be and am clueless as to how I find the frequency out of this question and compare the two stiffness.

2. Sep 16, 2009

### Staff: Mentor

You don't need the actual numbers. Set up a ratio of the frequencies. Hint: If the original spring constant is K, the new one is 2.2K.