How Do You Calculate Average Charge Density in a Cylinder?

Click For Summary

Homework Help Overview

The problem involves calculating the average charge density in a cylinder with a given charge distribution ρ = Cr², where C is a constant and r is the radial distance. The context is within the subject area of electrostatics and charge distributions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to integrate the charge distribution over the volume of the cylinder to find the total charge. There are questions regarding the initial approach of dividing the charge density by the length and whether that is too simplistic. Some participants suggest using cylindrical coordinates for the integration process.

Discussion Status

The discussion is ongoing, with various participants providing insights on how to set up the integration for the total charge. There is no explicit consensus yet, but multiple interpretations and methods are being explored, indicating a productive direction in the discussion.

Contextual Notes

Participants note the importance of integrating over the volume of the cylinder and the specific limits for the radius and length. There is an emphasis on using cylindrical coordinates for the calculations.

Roodles01
Messages
125
Reaction score
0

Homework Statement


A cylinder of radius a and length l has charge distribution

ρ=Cr2
where C is a constant and r is radial distance in cylindrical coordinates.
Derive an expression for the average charge density within the cylinder.

Homework Equations


Well, charge density given is within the volume, I think.
So for a point on the axis of the cylinder should be ρ divided by the length shouldn't it? Or is that being too simple?

The Attempt at a Solution



ρ = Cr2 / l
[/B]
Can someone confirm this or point me in the right direction, please.
 
Physics news on Phys.org
First you need to integrate the distribution over the cylinder to find the total charge.
 
∫ Cr2 dr

C ∫ r2 dr (0 < l < L)

CL3/3
 
The radius 0 < r < a .
The length L.

You need to integrate over the VOLUME of the cylinder to find the total charge in the volume. I advise working in cylindrical co-ordinates. where dV = rdrd\theta dz
 
s ρ(r) dV = Q

∫ Cr2 * 4πr2 dr = 4Cπ ∫ r4 dr

so
Q = 4CπR5 / 5
 
You need to integrate over the cylinder.

\int dV \ = \iiint rdrd\theta dz\ = \int_{0}^{L} dz \ \int_{0}^{2\pi}d\theta \int_{0}^{a}rdr This is the volume integral for a cylinder and as you can see, doing the integral gives the volume of a cylinder of radius, a, and length, L. But since your integrating a function over this volume, you want
\int \rho(r) dV You can split the integral similarly to find the total charge.
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
11K