How Does Temperature Scale Impact Gas Pressure Calculations in Thermometers?

AI Thread Summary
The discussion centers on calculating gas pressure at different temperatures using the ideal gas law. It highlights the need to convert Celsius to Kelvin for accurate calculations, as Kelvin is the absolute temperature scale necessary for thermodynamic equations. The formula P1/T1 = P2/T2 is emphasized for solving pressure changes, with an example using a pressure of 87.0 kPa at 104°C. Participants clarify that using Kelvin avoids negative values that can distort calculations. Understanding the importance of the absolute temperature scale is crucial for accurate gas pressure calculations in thermometers.
FishieKissie06
Messages
6
Reaction score
0
The gas in a constant-volume gas thermometer has a pressure of 87.0kPa at 104*C.

(a)what is the pressure of the gas at 50.0*C?
for this i used the eqn of (87/104)(104-50) like it said in the book and still didnt get the answer right.
 
Physics news on Phys.org
use P1/T1 = P2/T2 ...solve for P2

= (P1*T2)/(T1) = P2

don't forget to convert C to Kelvins.
 
but y would i convert to kelvins?
 
but y would i convert to kelvins?
 
"Why Kelvin?" Because there is no temperature scale other than the "absolute," or "thermodynamic" temperature scale, be it Kelvin or Rankine.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top