How much torque must the pin exert to keep the rod from rotating?

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SUMMARY

The discussion centers on calculating the torque required from a pin to prevent a rod from rotating, given specific parameters: rod length (L) of 1.011 meters, mass (M) of 3 kg, and an additional mass (m) of 0.301 kg. The equation used is Στ_net = 0 = τ_pin - τ_M - τ_m, where τ_pin represents the torque from the pin, τ_M is the torque due to the mass M, and τ_m is the torque due to the mass m. A critical error identified was the failure to convert mass to force by multiplying by the acceleration due to gravity (g), which is essential for accurate torque calculations.

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Homework Statement



How much torque must the pin exert to keep the rod from rotating?
(L=1.011m , M=3kg , m = .301kg)

So I am guessing the point of rotation is the pin??
But then how does the pin exert any torque if it is at the point of rotation?
I'm not quite sure


there is a sketch I've attached

Homework Equations



Ive used the equation [tex]\Sigma[/tex][tex]\tau[/tex]net=0=[tex]\tau[/tex]pin-[tex]\tau[/tex]M-[tex]\tau[/tex]m

The Attempt at a Solution


i have tried it so many ways and keep getting it wrong

[tex]\tau[/tex]pin = 3kg*(1.011m/2) + .301kg*1.011m
what am i doing wrong?
Please help thankyou
 

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For this type of problem, you probably don't need to worry about how the pin exerts a torque (though you can imagine in reality it would take a fair amount of force since there is only a small lever arm)

It looks like you've neglected to calculate the force of each of the masses and are using the mass instead (kg*m is not the units of force)
 


yeah thank you i did forget to multiply by the acceleration constant g
 

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