Motion of particle in an electric field

AI Thread Summary
A proton at rest in an electric field E(r) = E0 X-hat experiences a force given by Fproton = e * E(r), leading to an acceleration a = (e * E0) / m X-hat. Integrating this acceleration results in the velocity v = (e * E0 * t) / m X-hat and position x = (e * E0 * t²) / (2 * m) X-hat. The solution indicates that the position graph will be a parabola and the velocity graph will show a constant slope, consistent with motion under constant acceleration. The constants of integration are justified as zero due to the initial conditions of the proton being at rest. The calculations and reasoning presented are correct and align with the principles of classical mechanics.
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Homework Statement



Suppose a proton is at rest and at the origin of some coordinate system. Then, electric field of E(r) = E0 X-hat is turned on. What is the position of proton at time t and then its velocity?

Homework Equations



E(r) = E0 X-hat

Fproton = e * E(r)

The Attempt at a Solution



By using, Fproton = e * E(r), I obtained

ma = e * E0 X-hat
a = ( ( e * E0 ) / m ) X-hat

therefore, integrating the equation, I obtained

v = ( ( e * E0 * t ) / m ) X-hat
x = ( ( e * E0 * t2 ) / ( 2 * m ) ) X-hat

(note that constant of integration is ignored because initial v and x is zero)

So, the above answer should be correct right? And when we graph it we would have a parabola for x and a line of constant slope for v which is then similar to the model of an object under constant acceleration?

I'm just making sure since the answer to the question is pretty much straightforward that I'm afraid I'm missing something.

Thank you in advance!
 
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Falken_47 said:

Homework Statement



Suppose a proton is at rest and at the origin of some coordinate system. Then, electric field of E(r) = E0 X-hat is turned on. What is the position of proton at time t and then its velocity?

Homework Equations



E(r) = E0 X-hat

Fproton = e * E(r)

The Attempt at a Solution



By using, Fproton = e * E(r), I obtained

ma = e * E0 X-hat
a = ( ( e * E0 ) / m ) X-hat

therefore, integrating the equation, I obtained

v = ( ( e * E0 * t ) / m ) X-hat
x = ( ( e * E0 * t2 ) / ( 2 * m ) ) X-hat

(note that constant of integration is ignored because initial v and x is zero)

So, the above answer should be correct right? And when we graph it we would have a parabola for x and a line of constant slope for v which is then similar to the model of an object under constant acceleration?

I'm just making sure since the answer to the question is pretty much straightforward that I'm afraid I'm missing something.

Thank you in advance!
That all looks good.

Technically, you're not ignoring the constants of integration. You have actually given the justification for them to be zero.
 
Ok, thank you very much for the reply!
 
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