Newton's 2nd Law on light fixture

AI Thread Summary
The discussion revolves around a physics problem involving a lightweight string with three equal masses attached, creating four segments. The objective is to find the angle phi and the distance D, given that the angle theta is 40°. The participant attempted to solve the problem using the sum of vertical forces at the knots but initially misidentified the tension in the string segments. They clarified that the tensions differ across the knots and acknowledged that the horizontal components of tension cancel at each tie point. The symmetry of the setup implies that the tensions in the bottom segments of the string are equal.
jburt
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Homework Statement


A lightweight string of length 60.0 cm is attached to the ceiling at points separated by distance D, as shown on the diagram in my attachment. Three objects of equal mass are hung from the string, separating the string into four equal segments of lenth L. If θ=40°
, find the measure of angle phi and the distance D.

Homework Equations



please see attachment

The Attempt at a Solution



please see attachment
 

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I also want to say, I've attempted to use only the equations for the sum of y forces on the knots, since I've ruled the masses out as irrelevant, so those free body diagrams are also irrelevant. I subbed the value of T from the middle knot sumFy equation into the T for the 1st knot's sumFy equation and solved for phi. . . wrong answer resulted
 
L is the length of the pieces of the string, not the tension in them. The tensions are not the same in the different pieces at both sides of a knot.

ehild
 
I'd say that, at each tie point, the two horizontal components of the tensions cancel.
 
Thanks,

So, on my free body diagram on the 1st knot from the left, say I label the mg T, as T1, then T2 (upper left) and T3 (upper right), then for the middle knot, the same T1 from the mg (since equal mass=equal weight), but the tensions on either sides are BOTH T3 (equal, but opposite, right? due to same L)?? That's what I'm going to attempt.
 
It will be all right. The right-hand part is mirror image of the left-hand part because of the equal lengths and masses, therefore the tensions are the same in the bottom pieces of the string.

ehildehild
 
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