Organic Chemistry - Alcohol Synthesis Problem

AI Thread Summary
The discussion revolves around synthesizing an alcohol from an alkyne using hydration reactions. Initial suggestions include hydrating the alkyne and substituting a hydroxyl group with a halide using PBr3, leading to an alkene with an alcohol group. However, corrections were made regarding the reaction steps, emphasizing the conversion of the alkyne to an alkene using Na/liq.NH3, followed by NBS to produce allyl bromide, which can then be hydrolyzed to yield the desired alcohol. The target compound is identified as 1,3-butanediol, with participants confirming that mixing an alkene with water can produce the desired alcohol. Overall, the conversation highlights various methods and corrections in the synthesis process.
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I have attached a file of the alcohol I need to synthesize and my futile attempt... I was thinking of using a hydration reaction to make the alcohol from the alkyne group. So basically I would mix the alkyne group with H2O and some how produce the alcohol group.

Am I heading in the right direction?
 

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It's been a while since I've done Ochem, but here's my suggestion. Hydrate the alkyne, substitute a hydroxyl group with a halide using an equimolar amount of a selective halide salt, like PBr3. The resulting aklene will be on the 1,2 position, and a antimarkovnikov addition of an alcohol should add an alcohol onto the 1 position, creating your desired substance.

By the way, you drew the alkyne incorrectly. It's always drawn in a straight line due to sp hybridization.

EDIT: Actually, what I said was wrong. I was thinking about it on the way to class, removal of the halide will result in the 2,3 alkene, the hydrogen on carbon 2 (the one with the hydroxyl group) will be removed. I'll think about this more.
 
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Hi!

STEP 1: convert the alkyne to an alkene using Na/liq.NH3 .
STEP 2: Use NBS(N-Bromosuccinimide) to get allyl bromide(CH3CH=CHCH2Br) which when reacted with aq.NaOH gives alcohol(CH3CH=CHCH2OH).
STEP 3: Acidic hydrolysis of this alcohol gives the required product.

Vineeth.
 
You're looking to form 1, 3 - butanediol I believe. I'm pretty sure you can mix an alkene with water to get an alcohol.

My organic chem is a bit rusty, but I believe (1 - hydroxy - 2 - butene) + H - OH should give you what you're looking for.
 
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