Particle energy through magnetic and electric field

AI Thread Summary
The discussion centers on why a magnetic field cannot increase the energy of a particle moving through it, as described by the force equation F = eE + ev X B. Participants explore the concept that the magnetic field acts perpendicular to the motion of the particle, resulting in no work being done and thus no energy increase. The conversation highlights the importance of understanding energy transformations, emphasizing that energy can only be increased through work done on the particle. One participant realizes that the key to the answer lies in recognizing that the work done is zero in a magnetic field context. Ultimately, the conclusion is that the magnetic field cannot perform work on the particle, preventing any increase in its energy.
Sonko
Messages
10
Reaction score
0

Homework Statement



Given the formula for the force on a charge in an electric and magnetic field is F = eE + ev X B
why can the magnetic fi eld never increase the energy of a particle that travels through
it

Homework Equations



N/A

The Attempt at a Solution



I really am not sure! I look at this and i know that the reason must be obvious and I'll kick myself for not getting it but I'm simply at a loss! The only thing i can think of right now is that the fields are perpendicular to the motion and will cancel out however this just doesn't make sense!
Any help would be appreciated in not just helping me find the answer but for helping me rid myself of the stupidity I'm feeling! Thanks
 
Physics news on Phys.org
When does the kinetic energy of particle increase? In other words, how does energy get pumped into the particle?
 
umm I'm not completely sure what you mean? do you mean to use E^2 = p^2 + m^2 and show there is no overall change in momentum?
 
This is not necessarily a relativistic situation. If the kinetic energy of a particle increases, this means that there has been an energy transformation. What must be done on the particle to achieve this energy transformation? Hint: It starts with "W".
 
i woke this morning and came to my sense using your first clue! showing that Work done (and so the change in energy) was not increased.

thanks for the help on the subject!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top