How Does Mercury's Density Affect Column Pressure in hPa?

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To calculate the pressure of a 10 cm high column of mercury with a density of 13.6 g/cm³, the formula Pressure = pgh is used, where p is the density, g is the acceleration due to gravity (9.81 m/s²), and h is the height in meters. The density unit "g" in 13.6 g/cm³ indicates grams, not related to the gravitational constant. The unit hPa stands for hectopascals, which is 100 times a pascal (Pa). The calculation should maintain consistent units to ensure accuracy. Understanding these units and conversions is essential for accurate pressure calculations.
teng125
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What is the pressure of a 10 cm high column of mercury
(ρ = 13,6 g/cm^3) in hPa?

i know that the formula is Pressure=pgh so i subs in 13.6g/cm^3 (9.81m/s^2) (10cm).
may i know what is the g in 13.6g/cm^3 belongs to??

is it equals to 9.81m/s^2??
and also what is hPa??i know Pa is pascal but don't know h

anybody pls help
thanx
 
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hPa is 10^2, so 100 times a Pa. And assume g is 9.81ms^-2. I'm not sure what you mean "what the 'g' in 13.6g/cm^3 belongs to" question, but g is not a variable in there, it's an indication that the density is in grams per centimeter cubed, so keep the units in centimeters and grams, and the answer should be ok.

Levi
 
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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