The discussion centers on calculating the acceleration of a 9N block relative to a small pulley in a pulley system. The correct acceleration is determined to be g/4, with the overall acceleration of the system calculated as 3g/4 m/s². The difference in tension between the strings supporting the 3N and 9N particles is attributed to the rotational inertia of the small pulley, which affects the motion dynamics of the blocks.
PREREQUISITESPhysics students, mechanical engineers, and anyone studying dynamics and motion in pulley systems will benefit from this discussion.
The small pulley has rotational inertia. Therefore, the tension on the string supporting the 3N particle is different than tension on the string supporting the 9N particle.pcpssam said:[IMG ]http://upload.lsforum.net/users/public/v48021i223.png[/PLAIN]
for part(i) the answer is g/4 + g/2 = 3g/4 ms^-2
how to calculate the acceleration of the 9N block relative to the small pulley to be g/4??
Did I miss something?
thank you so much!