pcpssam
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for part(i) the answer is g/4 + g/2 = 3g/4 ms^-2
how to calculate the acceleration of the 9N blcok relative to the small pulley to be g/4??
Did I miss something?
thank you so much!
Question about pulley with relative motion
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for part(i) the answer is g/4 + g/2 = 3g/4 ms^-2
how to calculate the acceleration of the 9N blcok relative to the small pulley to be g/4??
Did I miss something?
thank you so much!
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The small pulley has rotational inertia. Therefore, the tension on the string supporting the 3N particle is different than tension on the string supporting the 9N particle.pcpssam said:[IMG ]http://upload.lsforum.net/users/public/v48021i223.png[/PLAIN]
for part(i) the answer is g/4 + g/2 = 3g/4 ms^-2
how to calculate the acceleration of the 9N block relative to the small pulley to be g/4??
Did I miss something?
thank you so much!