- #1
karan000
- 8
- 1
Homework Statement
Both diodes are ideal.
Answers:
(a) Vi
(b) -Vi
(c) -2Vi
(d) none of the above
Homework Equations
Q=CV
The Attempt at a Solution
1. For t=0 to Pi:
Cap1 and Cap2 are in series and hence Q1=Q2, therefore Vc1 = Vc2.
From this we get Vi = Vc1 + Vc2, hence Vc1 =Vc2 = Vi/2.
2. For t=Pi to 2Pi,
The circuit should look like 3 batteries in series as such:
Therefore Vo = -(Vi + Vi/2 + Vi/2) = -2Vi,
And so the answer is (c).
BUT...
Couldn't the circuit look like this too?
And so Vo = - (1.5Vi - 0.5Vi) = -Vi
Thus the answer is (b) ?
BUT...
We are just taking the voltage drop across the resistor, so Vo= Vc2 = 1/2Vi
So the answer is (d).Which is correct and what exactly am I misunderstanding?
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