Relativistic effects on an electron

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Homework Help Overview

The problem involves an electron accelerated through a potential of 10^9 Volts, with a focus on calculating its energy, kinetic energy, and momentum in the lab reference frame. The subject area pertains to relativistic physics and the effects of high-speed motion on particle properties.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of classical versus relativistic formulas for kinetic energy, questioning the validity of classical expressions at high speeds. There is an exploration of how to relate kinetic energy to the potential difference and the implications of the calculated values for γ and β.

Discussion Status

Some participants have offered guidance on using the relativistic kinetic energy formula and have confirmed the relationship between eV and the kinetic energy of the electron. There is an ongoing examination of the calculations, with some participants noting discrepancies in the values obtained for γ.

Contextual Notes

Participants are navigating the complexities of relativistic effects, particularly in relation to the high potential difference and the resulting speeds approaching the speed of light. There is a recognition of the need to adjust calculations based on relativistic principles, and some confusion remains regarding the correct application of these principles.

khfrekek92
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Homework Statement


An electron is accelerated through a potential of 10^9 Volts. What is the Energy, Kinetic Energy, and Momentum in the lab reference frame?


Homework Equations


(1/2)mv^2=eV=1.6E-10 J=1000 MeV



The Attempt at a Solution


Solving for the kinetic energy gives 1000 MeV, which then solving for v gives 2E10 m/s, which is greater than the speed of light.. In the rest frame of the electron, E=mc^2=8.2E-14 J, then I need to multiply that by γ to get the energy in the lab reference frame, but I can't solve for v, because I got v>c. What am I doing wrong??

Thanks in advance!
 
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You're using the classical expression for kinetic energy, which isn't valid at high speeds. You need to use the relativistic formula.
 
So would (γ-1)mc^2=eV now? I know I have to use relativistic kinetic energy, but I just don't know how to relate it to the potential difference. :(
 
Yes, that's right. What does the eV stand for on the righthand side of that equation?
 
eV would be the electron charge times the potential, right? And also, since it is an electron, wouldn't the Kinetic energy just be 10^9 eV=10000MeV? Then I can use this and E=γmc^2 where mc^2 is the rest mass and E=K+mc^2? Then solving for gamme, I get γ=19570.9, making β=.999999999. This seems a little too high, but 10^9 V is a lot too...
 
khfrekek92 said:
eV would be the electron charge times the potential, right?
Yup, I just asked because you said you didn't know how to work in the potential difference but it was already in your equation.
And also, since it is an electron, wouldn't the Kinetic energy just be 10^9 eV=10000MeV?
1000 MeV, like you said in your first post. You have an extra 0 this time.
Then I can use this and E=γmc^2 where mc^2 is the rest mass and E=K+mc^2? Then solving for gamme, I get γ=19570.9, making β=.999999999. This seems a little too high, but 10^9 V is a lot too...
Yes, that's exactly how you solve it, but your γ is off by a factor of 10. The mass of the electron, 0.511 MeV, is much smaller compared to its energy E, so it's very relativistic. You should expect a speed very close to c.
 

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