Rolling cylinder on an incline

AI Thread Summary
A cylinder of mass M and radius R rolls down an incline from height h, and its linear velocity at the bottom is calculated to be sqrt((4/3)gh). The discussion clarifies that angular momentum should not be expressed as mvsin(theta), as the angle is not necessary for determining the cylinder's speed. Linear momentum is equivalent to the momentum of the center of mass of the cylinder. The calculations rely on principles of energy conservation and rotational dynamics without needing the incline angle. Overall, the focus is on deriving these quantities based on mass, radius, and height alone.
andrewp7
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A cylinder of a mass M and a radius R starts at the top of a hill at a height h, and rolls to the bottom. At the bottom of the hill, what is its linear velocity, linear momentum, and angular momentum?


I believe the the velocity is sqrt((4/3)gh) and the the angular momentum is mvsin(theta) but I am not sure if those are right and I still d not know the linear momentum
 
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You have to give all quantities in terms of M, R, and h. Theta is not given. Look after the definition of angular momentum, it is not mvsin(theta). The linear momentum is the same as the momentum of the CM of the cylinder.

ehild
 
wouldn't I need some type of angle because it is on an incline?
 
Do you? You got the speed without the angle, don't you? How did you got it? Using what law?

ehild
 

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