Velocity of propagation of an EM field in vacuum

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SUMMARY

The velocity of propagation of an electromagnetic (EM) field in a vacuum can be determined using the relationship between the wave vector \( k \) and angular frequency \( \omega \), specifically \( k = \frac{\omega}{v} \). In this case, the magnetic field is given by \( \vec{B} = B_0 e^{ax} \sin{(ky - \omega t)} \hat{z} \). The propagation direction is along \( \hat{y} \), and the presence of the term \( e^{ax} \) does not alter the propagation speed, which remains equal to the speed of light \( c \) in vacuum.

PREREQUISITES
  • Understanding of electromagnetic wave equations
  • Familiarity with Maxwell's equations
  • Knowledge of wave propagation concepts
  • Basic calculus for differential equations
NEXT STEPS
  • Study the derivation of wave equations from Maxwell's equations
  • Learn about the significance of the wave vector \( k \) and angular frequency \( \omega \)
  • Explore the implications of exponential terms in wave functions
  • Investigate the relationship between electric and magnetic fields in EM waves
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Physics students, electrical engineers, and anyone studying electromagnetic theory or wave propagation in vacuum will benefit from this discussion.

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Homework Statement



In a region of empty space, the magnetic field is described by ##\vec{B} = B_0e^{ax}\sin{(ky-\omega t)} \hat{z}##. Find the speed of propagation ##\vec{v}## of this field.

Homework Equations



##\Delta \vec{B} = \frac{1}{v^2}\frac{d^2\vec{B}}{dt^2}## , ##k=\frac{\omega }{ v}##

The Attempt at a Solution



I'm not sure of a way to calculate the velocity. Do I have to take into account the equation, or because the wave is propagating in empty space can I simply say ##v=c##? And I know the direction of propagation would be ##\hat{y}## if the term ##e^{ax}## didn't exist, but is it still ##\hat{y}## with it? I really don't understand how that term affects the velocity of propagation.
 
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Try plugging your expression for B into Maxwell's equations.
 
I did that and got #\vec{E}#, but I still don't understand what equation to use to get the velocity.
 

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