Right answer for the Walter Lewin demo/paradox about electromagnetic induction in Lecture 16 ?
And greetings to you from sunny Essex UK.Walking clockwise through the loop, then the emf's have the right polarity, but the resistor drops are opposed to this direction. The sum will be ZERO
Using two voltmeters (in series) as in your "split" circuit, will give 0.2 Volts on each voltmeter.
For example, considering the upper left : 0.25 Vemf -0.05 Vdrop = 0.2V
and for upper right: - 0.25Vemf +0.45 Vdrop = 0.2 V etc...So the sum of both voltmeters will be 0.4 Volts and not 0.8 Volts!
Note that in the first (left) case your voltmeter Hi is connected to the positive side of the emf, but in the right case the voltmeter Hi is pointing to the negative side of the emf.
Hope this will help to understand also the rest of my video and thanks for watching it.
Best greetings from Belgium
This is a cool experiment, which demonstrates that the induced electric field ## (E_i) ## is evenly distributed over every elemental length of the single-loop circuit. Thank you very much for your efforts and sharing.Right answer for the Walter Lewin demo/paradox about electromagnetic induction in Lecture 16 ?
Yes! I'll spare y'all the diatribe I wrote in a related post a while ago. But just point out that Kirchhoff's voltage and current laws are for LUMPED ELEMENT CIRCUITS. If you want to use them in the presence of induced emf, you must put some inductors in your schematic. This, of course, is why lumped element models don't work sometimes.Still, he was spot-on redressing Lewin for his Kirchhoff remark, synthesizing the actual voltages around the ring
Let's take a look at how the distinguished Professor Lewin explained the build up of charges in the circuit and the role of these charges in the overall electric field. I think this is a good explanation.Failure to identify the two electric fields of differing sources (Ec from charges only and Ei from induction is I feel a serious omission. For one thing, had he been asked if & where charges are produced...
Thank you for that! I am happy to agree that with this video Dr Lewin has fully and correctly explained split E fields and the necessary buildup of charge in a resistively asymmetrical ring. I am in total agreement (except see below).Let's take a look at how the distinguished Professor Lewin explained the build up of charges in the circuit and the role of these charges in the overall electric field. I think this is a good explanation.
This video is relatively long, maybe we can watch it from 34 minutes.
Yes, this is the definition of potential difference.signify potential difference, the E must be replaced by what you called Ec.