Water equivalent of calorimeter

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Homework Help Overview

The discussion revolves around calculating the water equivalent of a calorimeter, involving concepts of specific heat and thermal equilibrium. The original poster presents a problem involving a calorimeter with given mass and specific heat, seeking to understand how to approach the calculation without knowing the equilibrium temperature.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss setting up an equation relating the heat transfer for the calorimeter and water, questioning whether they can cancel temperature terms. There is also exploration of the implications of specific heat and the potential confusion with specific gravity.

Discussion Status

The discussion is ongoing, with participants providing guidance on simplifying the setup and confirming the correctness of the original poster's understanding. There is acknowledgment of a discrepancy between the calculated mass and the expected answer, prompting further exploration of the problem's assumptions.

Contextual Notes

Participants note the lack of clarity in the problem statement regarding units for specific heat, which may lead to confusion in calculations. The original poster's approach is validated, but the discussion highlights potential ambiguities in the question itself.

rasen58
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Homework Statement


The water equivalent in kg, of a calorimeter having a mass of 0.3 kg and a specific heat of 0.2 is

Homework Equations


q=cmT

The Attempt at a Solution


I wanted to set cmT = cmT for the water and calorimeter, but I don't know what the equilibrium temperature is.
So what do I do?
 
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rasen58 said:
I wanted to set cmT = cmT for the water and calorimeter
That's good. Simplify what you set up, and you're in business.
 
Can I cancel out the T's then?
In that case, I would have c1m1 = c2m2
(0.2)(0.3) = (4.186)m2
m2 = 0.014 kg

But the answer says it's 0.06 kg
 
rasen58 said:
Can I cancel out the T's then?
Yes.
rasen58 said:
But the answer says it's 0.06 kg
You have met one of many sloppily stated questions you'll run into in your life. "Specific heat" has been conflated with "Specific gravity." Since water has a specific gravity of "One," the author of the question has chosen "One" as the specific heat for water as well. In kcal/kg, yes, but there is no specification of units in the problem statement.

Your understanding is correct, and your application of that understanding is correct.
 

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