Water equivalent of calorimeter

AI Thread Summary
The discussion revolves around calculating the water equivalent of a calorimeter with a mass of 0.3 kg and a specific heat of 0.2. The participant initially struggles with determining the equilibrium temperature and whether to cancel out the temperature variable in the equation. It is clarified that the relationship can be simplified to c1m1 = c2m2, leading to a calculation of 0.014 kg for the water mass. However, confusion arises as the expected answer is 0.06 kg, attributed to a misunderstanding of specific heat and specific gravity in the problem statement. The participant's approach is validated, emphasizing the importance of clear problem definitions in physics.
rasen58
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Homework Statement


The water equivalent in kg, of a calorimeter having a mass of 0.3 kg and a specific heat of 0.2 is

Homework Equations


q=cmT

The Attempt at a Solution


I wanted to set cmT = cmT for the water and calorimeter, but I don't know what the equilibrium temperature is.
So what do I do?
 
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rasen58 said:
I wanted to set cmT = cmT for the water and calorimeter
That's good. Simplify what you set up, and you're in business.
 
Can I cancel out the T's then?
In that case, I would have c1m1 = c2m2
(0.2)(0.3) = (4.186)m2
m2 = 0.014 kg

But the answer says it's 0.06 kg
 
rasen58 said:
Can I cancel out the T's then?
Yes.
rasen58 said:
But the answer says it's 0.06 kg
You have met one of many sloppily stated questions you'll run into in your life. "Specific heat" has been conflated with "Specific gravity." Since water has a specific gravity of "One," the author of the question has chosen "One" as the specific heat for water as well. In kcal/kg, yes, but there is no specification of units in the problem statement.

Your understanding is correct, and your application of that understanding is correct.
 
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