What is the accelerating force of a bullet in a 10cm gun barrel?

AI Thread Summary
To find the accelerating force of a 10g bullet in a 10cm gun barrel, first convert the mass to kilograms and the length to meters. Using the equation v^2 = vo^2 + 2a(x - xo), rearrange to solve for acceleration (a). Then, apply F = ma to calculate the force. The initial confusion stemmed from unit conversion, which is crucial for accurate results. Proper attention to units is essential in physics calculations.
Gradyjenkinz
Messages
6
Reaction score
1

Homework Statement

[/B]A 10g bullet accelerates from rest to 500m/s in a gun barrel of length 10cm. Find the accelerating force (assuming it is constant).

Homework Equations


F=ma, v^2=vo^2+2a(x-xo)?

The Attempt at a Solution


I tried using F=ma, but it does not equal the answer in the back of the book.
 
Physics news on Phys.org
Have you converted the mass and length into kg and m? Then rearrange v2=vo2+2ax to find a. Then sub that into F=ma.
 
  • Like
Likes Gradyjenkinz
Issy04 said:
Have you converted the mass and length into kg and m? Then rearrange v2=vo2+2ax to find a. Then sub that into F=ma.
Oh jeez. Got it now, thank you. Gotta make sure I actually pay attention to units :(
 
  • Like
Likes Issy04
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top