What is the acceleration of the box?

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To determine the acceleration of the box being pulled with a force of 138 N at an angle of 23.9°, the student must resolve the force into horizontal and vertical components and apply Newton's second law (F=ma). For the box on the rough wooden floor, a constant force of 2.2 N indicates the need to calculate the coefficient of sliding friction using the mass and force applied. The problem involving the 12.6 kg bucket requires analyzing the tension of 127.6 N to find its acceleration, considering the direction of the force. The student has successfully created force diagrams but needs to further develop the equations for both x and y directions. Overall, applying these principles will lead to the correct calculations of acceleration for each scenario.
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Homework Statement



A student pulls a box of books on a smooth horizontal floor with a force of 138 N in a direction of 23.9° above the horizontal. If the mass of the box and the books is 51.6 kg, what is the acceleration of the box?

A constant force of 2.2 N is required to drag a 49.2 kg box across a rough wooden floor at a constant speed of 2.2 m/s. Find the coefficient of sliding friction between the floor and the box.

A 12.6 kg bucket is lowered vertically by a rope in which there is 127.6 N of tension at a given instant. What is the acceleration of the bucket? When giving you answer, assume the acceleration is positive if up and negative if down.

Homework Equations





The Attempt at a Solution



I was able to draw force diagrams, but that's all.
 
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Now use those force diagrams to write out F=ma equations, separating your force vectors into horizontal and vertical components.
 
Next, write out Newton's second law for both the x and y directions.
 
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