What is the relation of sinθ and time in projectile motion with angle

AI Thread Summary
The relationship between sinθ and time of flight in projectile motion, given a constant velocity, is directly proportional, as indicated by the equation t = (2u sinθ) / g. When plotting time of flight against the angle of projection, the graph resembles a sine curve rather than a parabola, peaking at θ = 90°. The relationship remains unchanged at an angle of 45°, and the maximum time of flight occurs at 90°. The discussion highlights the importance of understanding the distinction between the relationship of time with sinθ versus the angle θ itself. This clarification emphasizes the linear nature of the relationship between time and sinθ.
xunok123
Messages
2
Reaction score
0

Homework Statement


I am wondering what is the relation of sinθ & time of flight in projectile motion with angle.
(under the case of same velocity)
Is the graph of this in a parabola shape??

Homework Equations


t = (2u sinθ) / g
(u in constant)

The Attempt at a Solution


would it be correct that sinθ ∝ time of flight ?

would the relation be affected after the angle of projection is lager than 45?

:cry: This puzzles me a lot...~_~
 
Physics news on Phys.org
xunok123 said:

Homework Statement


I am wondering what is the relation of sinθ & time of flight in projectile motion with angle.
(under the case of same velocity)
Is the graph of this in a parabola shape??

Homework Equations


t = (2u sinθ) / g
(u in constant)

The Attempt at a Solution


would it be correct that sinθ ∝ time of flight ?

would the relation be affected after the angle of projection is lager than 45?
Welcome to PF!

If you want to plot time of flight vs. angle I would put θ on the x-axis and t on the y axis. The graph would be a sine curve, not a parabola. It is similar in appearance to a parabola, though. There is no change in the relation at θ=45° .

The range of θ is 0 → π (180°) and reaches a maximum at θ = π/2 (90°).

AM
 
Andrew Mason said:
Welcome to PF!

If you want to plot time of flight vs. angle I would put θ on the x-axis and t on the y axis. The graph would be a sine curve, not a parabola. It is similar in appearance to a parabola, though. There is no change in the relation at θ=45° .

The range of θ is 0 → π (180°) and reaches a maximum at θ = π/2 (90°).

AM

HI Manson! Thank you so much for your answer@@! It's a big surprise for me!
would u mind have a little more explanation on this phenomenon??
I find it so interesting that the graph would appear as a sine curve.
 
Last edited:
xunok123 said:
HI Manson! Thank you so much for your answer@@! It's a big surprise for me!
would u mind have a little more explanation on this phenomenon??
I find it so interesting that the graph would appears as a sine curve.

Why does it surprise you so much when you have an equation right in your original post that says t = (some stuff)*sin(theta) ?

Andrew Mason: didn't the OP want the relation between t and sin(theta), not the relation between t and theta? The former would be linear.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top