What is the Resistance Between A and B in a Circuit?

AI Thread Summary
The discussion centers on determining the resistance between points A and B in a circuit diagram. Participants express confusion about whether the resistors are in series or parallel and how to interpret the circuit's loops. Emphasis is placed on understanding the definitions of series and parallel connections, with a suggestion to redraw the circuit for clarity. It is noted that each resistor connects to the same input and output, indicating they are in parallel. The conversation concludes with a participant gaining clarity on the circuit configuration.
Kara386
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Homework Statement


In the circuit attached below, what's the resistance between A and B?

Homework Equations

The Attempt at a Solution


I'm finding it difficult to interpret this thing. Are resistors 1 and 2 in series or parallel? What does the loop above 1 and 2 actually do, in terms of how much current would flow round it? It has no components in it. I really have no idea what's going on in the diagram.

I'm guessing it involves Kirchhoff's current and voltage laws but I'm struggling to actually apply those here. Thanks for any help!
 

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This exact problem has shown up here several times. You need to just pay attention to the definitions of serial and parallel connections and redraw the circuit. That is that POINT of the exercise, actually, more than the answer. It's to force you to pay close attention to the definitions.
 
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phinds said:
This exact problem has shown up here several times. You need to just pay attention to the definitions of serial and parallel connections and redraw the circuit. That is that POINT of the exercise, actually, more than the answer. It's to force you to pay close attention to the definitions.
Are these just all in parallel? If I removed either of those loops I'd say what was left was three resistors in parallel, but what happens when there are two loops? Still just in parallel?
 
Kara386 said:
Are these just all in parallel? If I removed either of those loops I'd say what was left was three resistors in parallel, but what happens when there are two loops? Still just in parallel?
Yes, it's rather trivial to note that each of the resistors has one end hooked to the input and one to the output so they are obviously in parallel. You'll need to define what you mean by "two loops" to get an answer to that, but if you draw the diagram properly it will be obvious in any case.
 
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phinds said:
Yes, it's rather trivial to note that each of the resistors has one end hooked to the input and one to the output so they are obviously in parallel. You'll need to define what you mean by "two loops" to get an answer to that, but if you draw the diagram properly it will be obvious in any case.
I see it, thank you! :)
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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