Projectile Definition and 1000 Threads

I don't know how to solve projectile motion problems when there was no initial velocity given, also no final velocity, or time. Please help😭

Wild question. Even Chat GPT struggling. What I first attempted was to find the velocity by which the projectile with v1 falls down to the ground with. This part was easy. Kinetic energy gained = gravitational potential energy lost Let's define our coordinate frame as up vectors being positive...

This is just the object which is thrown theta angle below rhe horizontal. I fail to understand how to get the individual range of this. I tried but I am getting zero, can someone point out what is wrong in my method So ##R=ucos\theta*t ## ##\frac{h}{R}=tan\theta## Therefore ##h=Rtan\theta## We...

Like, i don't even understand what it means by the ball accelerating at 0.5m/s2. is it accelerating upwards constantly at 0.5m/s2? what about gravity? the answer given is weird. initial speed u = 5m/s and t = 10s it says time taken to go up is = time taken to go down. (why?) so total time...

I have tried to use the projectile motion to find Vx and Vy, however since the angle isn't given, I don't think this problem can be solved with only motion formulas (I did solve it with energy formulas).

I conceptually know how to solve this problem, what I struggle with is the direction of the acceleration. For example to solve the first question I need to find the horizontal displacement when the ball hits the ground. Therefore ##l_0= x(t_1)= x_0 + v_0 t_1##, where ##t_1## is the moment the...

May be It's a concept problem.

TL;DR Summary: Lagrangian for projectile motion in an inclined plane with negative slope. I am a bit unsure on how to find the Lagrangian for projectile motion in an inclined plane with negative slope. I can solve it using Newton Mechanics, but am a bit new to lagrangian mechanics. Also could...

Hello! I'm doing some research for a small project that I hope you can help me with. I'm not a math genius, I just have an idea. I have an Excel document of a projectile trajectory with an angle of 8 degrees. (Can be any angle.) Blue projectile trajectory. What I want to do is enter the...

I am going to use this coordinate system: According to the answer of the book, I think no force is acting on this projectile: Let's say at top of it's trajectory its velocity is ##u##. Conservation of energy : $$2E_0=\frac 1 2 m_1 v_1^2+\frac 1 2 m_2 v_2^2$$ Conservation of momentum in...

Ok, so to start, the easy part, the velocity in the horizontal x direction (vx): vx = 20m/(2.5s) = 8m/s So far so good, but then for the vertical y velocity (vy), my answer is different than the book. I use the equation for position in the y direction, set the y value to 0 (the 2.5s it takes...

I figured this would be a problem in some classical mechanics book but so far I can't find an answer anywhere. Assume there is no drag or lift, and since the planet is not rotating we don't have to worry about Coriolis effects. I'm working on a solution but I want to see if my work is correct...

my answer was D, which is correct considering the motion downwards eg, object thrown from a cliff but what if an object is moving up?like a football being kicked? i cant understand how this graph applies to that...

i solved it like this... s = ut + 1/2 at^2 t= 1.08 (from part a) u= 65 sin4.30 a= 9.81? or -9.81 the answer said -9.81 why? wouldn't acceleration change from -9.81 to +9.81 because it moves up then down??? its soo confusing...

Since the ball will follow a parabolic trajectory , i threw it into the coordinate plane with particle starting from the origin . $$y= kx^2$$ Differentiating wrt ##t## : $$ gt=2ku^2 t\implies u=\sqrt{\frac{g}{2k}}$$ where $$k=\frac{\sin\theta}{R\cos^2\theta}$$ Now , final speed when it reached...

Hi - I built an air cannon to launch a fishing lure for my science fair project. The air cannon launched a 1/4 oz lure 31.4 meters. Based on this, I calculated the initial velocity to be 17.54 m/s using the formula for range of a projectile. I want to be able to launch the lure 38.5 meters. I am...

A ball is thrown with an initial speed vi at an angle 𝜃i with the horizontal. The horizontal range of the ball is R, and the ball reaches a maximum height R/8. In terms of R and g, find the following. (a) the time interval during which the ball is in motion: Sroot(R/g) Correct (b) the ball's...

1) Bullet spin causes a bullet to become a gyroscope. Specifically, bullets have their center of pressure in front of their center of mass. Therefore, when pressed, gyroscopic forces cause a bullet to spin 90 degrees instead of tumble. See this diagram: 2)The precession does not cause the...

TL;DR Summary: Hi, I am a high schooler competing in a science competition building a trajectory to shoot the projectile similar to the one in the thread below. https://www.physicsforums.com/threads/aarons-gravitational-potential-energy-to-launch-projectile-science-competition.773745/ The 4...

Hi. Very simplified schematics of railguns all look like this: I have trouble properly understanding this. So apparently there is still a significant magnetic field where the projectile is, even though that's where the current stops flowing through the rails? Of course the magnetic field...

TL;DR Summary: Find initial vertically upward speed of the ball Find horizontal speed of the speed Find angle How to: Find initial vertically upward speed of the ball Find horizontal speed of the speed Find anglei try to solve it but it didn't work

TL;DR Summary: Find horizontal velocity? I have no idea how to solve the problem, the question only provide distance 16cm(h),3.6cm(v) and acceleration = 0

(a) Find the initial speed. Solution The relevant equations are (4) and (5) derived here and reproduced below as (1) and (2) respectively: $$\begin{align} & \frac{\Delta x}{\tan\!\theta-\tan\!\varphi}=\frac{2v_{0x}^2}{g} \\ & \tan\!\varphi=\frac{1}{2}(\tan\!\theta+\tan\!\omega)...

Vix=Vcosθ Vix=0.76604*V Xf=Vixt Xf=0.77604V*2 V=Xf/1.55208

For this problem, The solution is, I don't understand how they got from ##\frac {sin^2\theta_i}{sin2\theta} ## to ##\frac{tan\theta_i}{2}##. Would somebody please show me the immediate steps? I also don't understand is why they say the ignore the trivial case where ##\theta_i = 0~rad##...

TL;DR Summary: Using vector functions how can I find the minimum average velocity (something greater than 11.86m/s) of a ball if the launch angle is unknown and if I have a point that the object must travel through (11.86, 3.47)? In my assignment, I developed a function for a lob shot...

TL;DR Summary: I want to mainly figure out where in the problem solving I went wrong. I understand the correct answer (since I looked it up), but to me, it does not make any sense. I am honestly stumped at this point. Online solutions say that my equation y = 0.5774x-0.003354x^2 should...

i used t=d/v for the x direction using the formula t=250/vcos55 and subbed that into the formula for the y direction d = (v) (t) + (0.5) (a) (t)^2 35 = (vsin55) (250/vcos55) - (4.9) (250/vcos55)^2 canceled out the first two v 35 = sin55 (250/cos55) - (306250/v^2cos3025) 35 = 357 -...

My reasoning was to use this kinematic equation to first get time of flight of the baseball using horizontal components, and then use this same equation again to find initial velocity.

We know that if a projectile is thrown vertically, there will be a brief time when it momentarily stops. Can we calculate this brief moment?

I worked myself into a trigonometry rut. I've tried two approaches, first by not changing the frame of reference, and second by taking the incline as the horizontal x axis. Here is my second attempt: Take the incline as the horizontal. Then the coordinates of target T are: $$ \begin{align} x_T...

if the target is lower than me, the formula is below, but if it's higher as in the task, a whole different formula is required I think. a = 9.8 * distance^2 / velocity^2 phi = Arctan(distance / height_diff) angle_if_elevation = ( Arccos((a - height_diff) / Sqroot(height_diff^2) + distance^2)) +...

I have attempted the problem a few times, and have posted my work below. I thought to check my work using ## v_x t = v_1 \times \cos\theta \times t = \Delta x## to see if I get back expected results, and I did for the horizontal motion (the substitutions are from the numbered steps below): ##...

We know x = R =max range (28m) on level ground. Need to find v()^2. Subbing y=0 into (1) above, get v(0)^2 = (gR^2/)/(2*cos (theta)^2 * tan (theta). ... (2) This didn't seem right, since this means v(0)^2 is a negative number ... maybe my orientation or algebra wrong? Anyway, didn't see...

I've been trying some online projectile problems. Specifically, I was using this one on master difficulty, looking at row e. It uses a random number generator; I shared the data I received in the Homework Statement above. According to the help section, you can solve this with the formula...

26.6m/s = v0 36.5º = θ g = 9.81m/s^2 A) Find Range: (v0^2)/g *sin2θ = (26.6^2)/9.81 * sin2(36.5) = 89.99 I double-checked with the other Range equation (2v0*cosθ * (v0sinθ)/g) so I know I'm doing something wrong. Please help! Thank you edit: A) Correct answer is 69.0

I assumed the cyclist was going 60-kph. Then worked backwards as shown above to calculate the deceleration in the x direction and then the time to decelerate to a stop at 39 m. Then used this time to calculate the initial speed if cyclist thrown 39 m, which was 8.4 m/s. But if he was going...

I have a question about the Coriolis acceleration experienced by a projectile launched from the surface of a rotating body. Say a ball is launched at 45 degree angle relative to the surface at some initial velocity v0. Let's further specify that the ball is launched due north from the equator...

Mentor note: Moved from a technical forum section, so Homework Template is not present. Hello Physics Forums members, I am a student in AP Physics C and I was just working out the range of a projectile when air resistance is non-negligible. As of right now I'm going to use the linear model of...

I know the spring constant of my spring, 90.54 n/m The spring is stretched 13.5 cm Im launching of a deck that is 1.75 meters high

At first, I want to use conservation of momentum when the object explodes at the highest position but I think the projectile is not a closed system (there is weight acting on it). Tried conservation of energy but not enough information provided. What approach should I take for this question...

Hi, so I solved this using energy. I also tried solving this using kinematic equations. The issue I am running into s for calculating the Vy of the problem. I am able to find the time it takes the rock to fall using d=(1/2)gt^2. Then, I considered two different ways of going about finding the...

So first I found the velocity of the ball at the bottom of the swing from the force equations, which I got to be 4.9 m/s and this is only in the x-direction. Then using the projectile motion for delta y I found time, which is 0.2s. Then using that time I found the delta x to be 0.98m. I just...

Hi, I am a game developer and recently found myself in a situation where I wanted to create an enemy that shoots at you given a set of variables. The game takes place in a top down view so there is no need for gravity acceleration, just 2d linear constant movement. The question to answer is...

So using the projectile equation I got ##a\sin (\alpha + \beta) = v\sin (\alpha + \beta)t + \frac{g\sin \beta t^2}{2}## To find t we use the other projectile equation: Since the horizontal velocity must be 0 for it to hit the ground perpendicularly we set the equation to be: ##0 = v\sin (\alpha...

Calculated maximum range of arrow at 45 degrees with initial velocity measured horizontally is of course reduced by air resistance. BUT initial velocity at 45 is reduced because propulsive force is constant and gravity reduces velocity by about 3m/sec. So not all distance loss is drag. Authors...

Can I get a hint on how to start with this problem ? Thanks in advance I can't really think of anything...

Assuming it’s one body whose initial speed is u. First it attains height h then H. t1 and t2 are two times at which they attain h and H. ##h=ut1-\frac12gt1^2## ##H=ut2-\frac12gt2^2## ##\frac {t1}{t2}=1/3## Replacing t2 with 3t1, I am stuck.

I found the function of the range of the projectile launched from a cliff. R = vcos(x)((vsin(x))+sqrt(v^2sin^2(x)+2gh))/g I stopped here because I feel like taking the derivative and optimizing for maximum would spiral out of control. Is there another approach to this problem?