Absolute Temperature and the Ideal Gas Law

AI Thread Summary
The discussion revolves around calculating the new temperature of air in a car engine cylinder after compression. Using the Ideal Gas Law, the initial conditions are set with a volume of 4.50 x 10^-2 m^3, a temperature of 30°C, and atmospheric pressure. The air is compressed to one-ninth of its original volume and twenty times the original pressure. The calculation leads to a new temperature of approximately 673 K, which is equivalent to 400°C. This demonstrates the relationship between pressure, volume, and temperature in gas behavior under compression.
liz_p88
Messages
17
Reaction score
0

Homework Statement



A cylinder in a car engine takes Vi = 4.50 x 10^-2 m^3 of air into the chamber at 30°C and at atmospheric pressure. The piston then compresses the air to one-ninth of the original volume (0.111Vi) and to 20.0 times the original pressure (20.0 Pi). What is the new temperature of the air?

Homework Equations



P1V1/T1 = P2V2/T2

The Attempt at a Solution



I know I am supposed to convert my pressure and temperature to different numbers but I simply do not know what I am supposed to do. Please help!
 
Physics news on Phys.org
I figured it out.

(101 kPA)(.045 m^3)/303k = (2020 kPA)(.004995 m^3)/T2

673k or 400°C
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Why must we use absolute temperature for the Ideal Gas Law?
Replies
10
Views
3K
Adiabatic Expansion of Pressurized Air in a Piston-Cylinder Setup
Replies
8
Views
2K
Gas temperature in a constant volume
Replies
8
Views
2K
Why is temperature constant after gas has expanded?
Replies
33
Views
2K
Calculating Work Done by Gas at Constant Pressure
Replies
2
Views
2K
Open Gas Turbine - calculate T2, T3, T4, efficiency
Replies
1
Views
2K
Calculate ideal-gas temperature of a material
Replies
2
Views
2K
Mixing two ideal gases with different V, T at constant pressure
Replies
16
Views
3K
Why does a gas behave as ideal if the Isotherm and Isenthelp
Replies
3
Views
1K
What are the steps to solve a polytropic process problem?
Replies
6
Views
2K

Hot Threads

Recent Insights

Back
Top