Engineering Basic Circuit Analysis - confused about self polarity

AI Thread Summary
The discussion revolves around understanding self-polarity in circuit analysis, particularly in relation to transformers and AC voltage. A scenario is presented involving a single winding with a center tap, illustrating how voltage measurements remain consistent regardless of which half of the winding is driven. The concept of transformer action is emphasized, highlighting the importance of proper dot notation for windings. Additionally, the necessity of representing voltage drops as negative in certain circuit configurations is clarified, particularly in counter-clockwise directions. This foundational understanding is crucial for progressing to more complex circuit problems.
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This question is bugging me, and I think I need to get it answered before I move on to working on the "harder" problems. I hate being stumped by the little stuff like this. Anywas, I'm including the question that I have as an attachment, it will be easier for all.

Thank you!
 

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I'm not sure this will answer your question, but think of the case where you have a single long winding with a center tap. When you drive the full winding with an AC voltage, you see half that AC voltage at the center tap. Now drive just the first half of the winding with half of the AC voltage, and really nothing has changed, right? You still will measure half of the AC voltage on the second half of the winding, even though you are only driving the first half. That's because of the transformer action. Now think about how the dots would go on the two windings. If you dot the top of the first half winding, then you would dot the start of the second half winding at the center tap. You can also split the center tap, so that you have two separate windings, and the dots stay in the same places.
 
Yes, you have to make it negative. In the counter-clockwise direction (the second diagram), voltage drop across the inductor is I_1 (j4). If you represent all voltage drops in the negative (as what you did with the resistor), then this term should be in the negative too. Also, Vs should be in negative in the second equation as well since, in the counter-clockwise direction, there is a voltage drop across its terminals.
 

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