Calculating Electric Field at Origin due to Two Point Charges

Click For Summary
SUMMARY

The discussion focuses on calculating the net electric field at the origin due to two point charges: q1 (-4 nC) located at (0.600 m, 0.800 m) and q2 (+6 nC) at (0.600 m, 0). The user initially attempted to calculate the electric fields using the formula E = 1/(4πε₀) * q/r² but failed to account for the vector nature of electric fields. The correct approach involves breaking down the electric fields into their x and y components before summing them to find the resultant electric field at the origin.

PREREQUISITES
  • Understanding of electric field concepts and vector addition
  • Familiarity with Coulomb's law and the formula E = 1/(4πε₀) * q/r²
  • Basic knowledge of coordinate systems in physics
  • Ability to perform vector decomposition and addition
NEXT STEPS
  • Learn about vector decomposition in physics
  • Study the principles of superposition in electric fields
  • Explore examples of electric field calculations involving multiple charges
  • Review the concept of electric field lines and their representation
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone interested in understanding electric fields and their calculations involving multiple point charges.

hotmail590
Messages
52
Reaction score
0
A point charge q1 -4 nC is at the point x = 0.600 m, y = 0.800 m, and a second point charge q2 +6 nC is at the point x = 0.600 m, y = 0.
I need to calculate the magnitude of the net electric field at the origin due to these two point charges.
|
|....... q1 (0.6, 0.8)
|
|
|
|
|
Origin--------------------q2 (0.6, 0)
To solve this problem I was thinking of taking the distances of q1 and q2 from the origin and using that as the radius, I can plug into
E = 1/(4piEo) * q1/r^2 r = 1 q1= -4nC
and
E = 1/(4piEo) * q2/r^2 r = 0.6 q2= +6nC
and add them together to find the electric field at the origin.
however when I did that, the answer turned out to be incorrect.
What am I'm doing wrong? Thakn you for your help.
 
Physics news on Phys.org
Your distances are correct, but you're ignoring the fact that the electric fields from the two charges need to be added as vectors, not just numbers. You need to split the fields into components in the x and y directions, then add them.

Does that help?
 
ohh i understand now! thankyou@!
 

Similar threads

Replies
9
Views
5K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 10 ·
Replies
10
Views
3K