Calculating Momentum for a Slap Shot in Hockey

  • Thread starter Thread starter Chutzpah
  • Start date Start date
  • Tags Tags
    Momentum
AI Thread Summary
Brett's slap shot problem involves calculating the puck's final velocity after applying an average force of 16.8 Newtons for 0.116 seconds, starting from an initial speed of 3.4 m/s away from the goal. The impulse calculated is 1.95, which equals the change in momentum. To find the final velocity, the correct approach is to consider the direction towards the goal as positive, adjusting the signs accordingly. A separate car crash problem involves determining the stopping time from an initial speed of 13.7 m/s over a distance of 0.277 meters, which requires using constant acceleration equations correctly. Clarifications on the signs and assumptions about final velocity are crucial for solving both problems accurately.
Chutzpah
Messages
7
Reaction score
0
Brett takes a slap shot, exerting an average force of 16.8 Newtons on the puck for 0.116 seconds. The puck has a mass of 0.110 kilograms and was initially moving directly away from the goal at 3.4 meters per second. How fast does it move toward the goal?
21.127 or -21.127 is not the correct answer. I am unsure which direction would be considered negative momentum. Here is my work.
Impulse= 1.95
1.95=change in momentum
1.95= mass X change in velocity
1.95= .110kg X (vf-3.4)
I divided 1.95 by .110kg and then added 3.4 to the other side. According to my online homework checker this is wrong. Could someone please help me solve this overthought problem? Perhaps something isn't negative when it should be.
 
Physics news on Phys.org
To keep track of signs, do this: Pick one direction (towards the goal, say) and call that positive. Given that, what's the sign of the impulse? the initial velocity?
 
That's great I think I got it. Here is one problem that makes no sense to me even after using the given hint.
2. A car moving at 13.7 meters per second crashes into a barrier and stops in 0.277 meters.
a. How long does it take to stop the car? Hint: This is a constant acceleration problem.

So I used the const acc eq X=.5(vf+vi)t and got
.277=.5(13.7)t
t=.04

This can't be right. Where did I go wrong? I tired just multiplying the two givens together and that didn't work either. Was it wrong to assume the final velocity was 0? Thanks for your help.
 
this is correct.
why don't you like your answer?
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...

Similar threads

Back
Top