Continuous Charge Distributions

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Homework Help Overview

The problem involves calculating the electric field due to a continuous charge distribution along a string, with a uniform charge density specified. The charge density is given as 9.00 nC/m, and the electric field is to be determined at a point on the x-axis.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the setup of the integral for calculating the electric field and question the numerical results obtained. There is a focus on the constants involved, particularly the charge density's units.

Discussion Status

Some participants are verifying the setup of the integral and the constants used, while others are questioning the correctness of the numerical answer derived from the calculations. A participant identifies a potential issue with the units of the charge density.

Contextual Notes

There is an emphasis on ensuring the correct units are used for the charge density, which appears to have caused confusion in the calculations. The problem is framed within the context of homework constraints, suggesting a need for careful consideration of assumptions and definitions.

WarpSpeedo
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Homework Statement



A charge lies on a string that is stretched along an x-axis from x = 0 to x = 3.00 m; the charge density on the string is a uniform 9.00 nC/m. Determine the magnitude of the electric field at x = 8.00 m on the x axis.

Homework Equations


[itex] \int_0^3 kλ/(8-x)^2\,dx [/itex]

The Attempt at a Solution



k=8.99e9
λ=9

I know k and λ can come out of the integral leaving 1/(8-x^2). which gives me 9.44e-10 which webassign marks wrong.
 
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Your set-up looks fine, but I don't get anything close to the numerical answer you're getting.
 
WarpSpeedo said:

The Attempt at a Solution



k=8.99e9
λ=9

I know k and λ can come out of the integral leaving 1/(8-x^2). which gives me 9.44e-10 which webassign marks wrong.

Are you thinking about the units for λ?
 
Problem was the units for λ. Thanks for your help
 

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