Electric field from a circle arc

AI Thread Summary
To find the x-component of the electric field at the origin from a circular arc with a charge of 3.8 μC and a radius of 1.9 m, the relevant equations include E = kq/r^2 and dq = λ dθ. The user attempted to integrate using the formula E = kq/r^2 * sinθ, leading to a calculation of kq/r^2 ∫(sinθ/θ) dθ. However, the integral approach resulted in an incorrect answer of 12968.1 N/C. The discussion suggests substituting values for λ and ds to correctly evaluate the integral from θ = 0 to π/2 for accurate results.
nautola
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Homework Statement


Find the x-component of the electric field
at the origin due to the full arc length
for a charge of 3.8 μC and a radius of
1.9 m. The value of the Coulomb constant
is 8.98755 × 109 N · m2/C2.


Homework Equations


E = kq/r^2
dq = q dθ
λ = Q/ (R θ)


The Attempt at a Solution


I said E = kq/r^2
And so Ex = kq/r2 * sinθ
and dEx = k*dq/r2 * sinθ
and dq = λ ds
ds = R dθ
λ = q/s
so dq = Q/θ dθ

I get kq/r2 ∫sinθ/ θ dθ

But when I input the answer from this integral (from the calculator) the answer is wrong.
 

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What is your answer?
 
I got 12968.1 N/C. Is my method correct?
 
I don't think so.
dq = λ*ds, where
λ= q / s , ds = r*dθ and s = πr/2
Substituute these values in the expression of dE and find the integration taking limits θ = 0 to π/2
 
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