- #1
rugapark
- 22
- 0
I am given F=(3i + 2j + 4k) N and mass = 2kg
I need to calculate acceleration, so I plugged it into F=ma,
am I right in saying
(3i + 2j + 4k) = 2 a
[tex]\frac{(3i + 2j + 4k)}{2}[/tex] = a
therefore a = 1.5i + 1j + 2k ?
cheers.
I need to calculate acceleration, so I plugged it into F=ma,
am I right in saying
(3i + 2j + 4k) = 2 a
[tex]\frac{(3i + 2j + 4k)}{2}[/tex] = a
therefore a = 1.5i + 1j + 2k ?
cheers.