How to Calculate the Specific Heat Capacity of the Calorimeter?

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To calculate the specific heat capacity of the calorimeter, the heat gained by the calorimeter must be determined using the equation Q = mcθ. The heat lost by the brass and the heat gained by the oil and calorimeter must balance, leading to the equation Qbrass = Qoil + Qcal. The calculations show that the heat from the oil is 1489.6 J and from the brass is 2940 J. The temperature change for the calorimeter is confirmed to be 14°C, as it shares the same temperature change as the oil. This analysis leads to the conclusion that the specific heat capacity can be calculated once the heat gained by the calorimeter is established.
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Homework Statement



A calorimeter contains of 70g oils at temperature of 30oC.If a piece of brass with a mass of 125g heat up until 100oC.After that a brass put in that calorimeter and final temperature of the mixed is 44oC.Calculate the specific heat capacity (c) of the calorimeter if its mass is 100g.(Given c of oil =1.52Jg-1oC-1 & c of brass =0.42Jg-1oC-1)

Homework Equations



Q=mcθ

The Attempt at a Solution



Qoil=70(1.52)(14)=1489.6J
Qbrass=125(0.42)(56)=2940J

Then I stuck.How to find temperature & Q of calorimeter?
 
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Qoil=70(1.52)(14)=1489.6J
Qbrass=125(0.42)(56)=2940J

Find heat gained by the calorimeter. And then

Qbrass = Qoil + Qcal.
 
Thanks for the help,but just to make sure,is temperature change for calorimeter=44-30=14?
 
kai92 said:
Thanks for the help,but just to make sure,is temperature change for calorimeter=44-30=14?

Yes. Oil is in the calorimeter. So the change in temperature of oil and the calorimeter is the same.
 

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