Three light waves combine at a point find resultant amplitude and phase angle

Click For Summary

Homework Help Overview

The problem involves the combination of three light waves at a point, represented by their electric field components. The objective is to find the resultant amplitude and phase angle of the combined electric field.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss different methods for combining the electric field components, including adding them sequentially or all at once. There is a question about the validity of using double angle formulas and whether the initial assumptions about the approach are correct.

Discussion Status

Some participants have provided guidance on the methods to use, and there is a recognition of the results obtained from different approaches. The discussion reflects a mix of interpretations and methods without a clear consensus on the correctness of the results.

Contextual Notes

There is an emphasis on careful examination of phase shifts and their effects on the resultant amplitude, with some participants noting the cancellation of terms due to opposing phase shifts.

CianM
Messages
3
Reaction score
0

Homework Statement


Three light waves combine at a point where their electric field components are

E1 = Eo[tex]sin \omega[/tex]t

E2 = Eo[tex]sin (\omega[/tex]t - 2[tex]\pi[/tex]/3)

E3 = Eo[tex]sin (\omega[/tex]t + [tex]\pi[/tex]/3)

Find the resultant amplitude of the electric field ER at that point and it's phase angle[tex]\beta[/tex]
Write the resultant wav int the form E = ER[tex]sin(\omega[/tex]t + [tex]\beta[/tex])

Homework Equations





The Attempt at a Solution



Am I right in assuming that first you add E1+E2 then add E12 + E3 using double angle formulas? Or am I going about this completely the wrong way?
 
Physics news on Phys.org
What about adding all three at once, using dbl angle formula to break out the phase shifts and collecting like terms. The results should be the same.
 
Well I already did the way I suggested and the answer I got was :
ER = 2Eo sin ([tex]\omega[/tex]t)cos([tex]\pi[/tex]/3)
taking cos([tex]\pi[/tex]/3) = 1/2
then equals ER = Eosin( [tex]\omega[/tex]t) .
Is this right?
 
yep, some careful examination of the problem shows that the -phase shift term is equal and opposite to the positive shift term, cancelling out, leaving your result. (in other words the two phase angles sum to pi)
 
Last edited:
Ok. Thanks for your help!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
3
Views
7K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 29 ·
Replies
29
Views
4K
Replies
1
Views
2K