Understanding Voltage Distribution in AC Circuits

AI Thread Summary
The discussion centers on the voltage distribution in AC circuits, specifically addressing why the potential at points C and D can be set equal while points A and B are zero. It highlights the application of Kirchhoff's laws, noting that the voltage across components C1 and C2 is equal, which leads to confusion regarding current flow despite equal voltages. The explanation clarifies that current can still flow between points A and B if the resistance is zero, resulting in equal voltages at those points. This resolves the confusion about the existence of current with equal voltages. Understanding these principles is crucial for analyzing AC circuits effectively.
phantomvommand
Messages
287
Reaction score
39
Homework Statement
This is the electricity problem from 1983 IPhO. I am confused about a small part of the answer, and understand the rest of the solution, so you guys do not have to go through the entire solution. I am only asking about part b.
Relevant Equations
Q = CV,
Kirchoff's laws
The problem is shown below: (I am only asking about part b)
Screenshot 2021-02-26 at 11.27.36 PM.png

^Above is the problem.

Below is the solution to part b. They have claimed that we can set potential at C = D = u(t), and A=B=0. Why is this claim true?

What I realize:
By applying Kirchoff's across ACDB, Voltage across C1 = Voltage across C2. But the claim that Voltage at C = Voltage at D seems impossible to me. How can there still be a current flowing through CD (denoted by i5), if Vc = Vd? Likewise, how can i5 exist between AB if Va = Vb = 0?

You may refer to the full solution here: https://www.jyu.fi/tdk/kastdk/olympiads/problems.html#83prob (if I have not given enough context).
Screenshot 2021-02-26 at 11.30.01 PM.png

Thank you!
 
Physics news on Phys.org
Thanks for posting a problem from a beautiful era, the era of my youth. 80s were the best era of my life.
Now for your question:
We can have any current between two points A and B as long as the resistance between the two points is zero. By Ohm's law we ll have $$V_{AB}=R_{AB}I_{AB}=0I_{AB}=0\Rightarrow V_A-V_B=0\Rightarrow V_A=V_B$$
 
thanks for this... I must have been so confused :<
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top